Each 32-watt bulb in a 48-inch fluorescent light typically draws around 0.27 amps. Therefore, a two-bulb setup would draw approximately 0.54 amps in total.
1 amp
Depends on the size of the LED light and the voltage applied. An example is an LED 24 volt globe light that pulls 8 watts which draw 0.333333 amps. Take an LED 120 volt light bulb draws 12 watts and will pull 0.1 amps. The same bulb at 240 volts wil draw 0.05 amps. it really depends on the watts and voltage applied. An average would be about 0.1 amps.
The 194 bulb is ~3.8 watts, at 14 volts they draw 0.271 amps.
A 65 Watt incandescent light bulb should draw 65W/120V = 541.67mA
About 0.6 amps for a 12v 21w bulb
Each 32-watt bulb in a 48-inch fluorescent light typically draws around 0.27 amps. Therefore, a two-bulb setup would draw approximately 0.54 amps in total.
It is drawing .06 amps.
1 amp
The question isn't what you're powering with a particular gauge of wire, but what's the current draw. If the metal halide light can run on a 15 Amp breaker (from the breaker panel), fine use your metal halide in your residential application and run it on the 14 gauge wire.
Depends on the size of the LED light and the voltage applied. An example is an LED 24 volt globe light that pulls 8 watts which draw 0.333333 amps. Take an LED 120 volt light bulb draws 12 watts and will pull 0.1 amps. The same bulb at 240 volts wil draw 0.05 amps. it really depends on the watts and voltage applied. An average would be about 0.1 amps.
The 194 bulb is ~3.8 watts, at 14 volts they draw 0.271 amps.
A 65 Watt incandescent light bulb should draw 65W/120V = 541.67mA
The equation that you are looking for is I = E/R. Amps = Voltage/Resistance in ohms.
No, they do not draw the same current. The current drawn by an electrical device is determined by the power (Watts) and voltage (Volts) using the formula: Current (amps) = Power (Watts) / Voltage (Volts). So, the 12 volt 50 watt bulb will draw higher current compared to the 230 volt 50 watt bulb.
Watts = Volts x Amps x Power Factor. An incandescent light bulb is a resistive load so PF = 1. ANSWER: = 1/2 Amp
It's 75/120 and the answer is in amps.