Each 32-watt bulb in a 48-inch fluorescent light typically draws around 0.27 amps. Therefore, a two-bulb setup would draw approximately 0.54 amps in total.
1 amp
A 65 Watt incandescent light bulb should draw 65W/120V = 541.67mA
To determine the amperage drawn by a 250-watt metal halide bulb, you can use the formula: Amps = Watts / Volts. Assuming the bulb operates on a standard voltage of 120 volts, it would draw approximately 2.08 amps (250 watts / 120 volts). If it operates at 240 volts, it would draw about 1.04 amps (250 watts / 240 volts). Always check the specific voltage rating for accurate calculations.
A lumen is a measure of how much total light a bulb produces. Incandescent (1156) bulbs spray their light through almost 360 degrees and lamp housings designed for them rely on that. Most LED lamps put all their light out in a narrow cone and work poorly with standard 1156 housings. However, there are LED assemblies that have their light-producing chips arranged around a sphere and they work well in standard housings. The LEDs you see on commercial vehicles are mounted in housings designed for their narrow cone output, that's why they look bright. A standard 1156 bulb puts out about 400 lumens when new. As of January 2010, I haven't found an LED replacement that puts out any more, and most are only 50 lumens or so, not enough for a standard 1156 housing. To confirm the above: From Bosch Automotive Handbook7th ed. a 1156 (BA15S) Stop/Turn 21W bulb puts out 460 lumens. For a 5W Side marker / Tail BA15S it is 50 lumens (strangely low, I know) and 10W Tail light 125 lumens. If replacing with a warm white LED, then that is how many lumens you need to match the brightness (as well as light direction being good). BUT, if using a Red LED for a brake light or an Amber LED for Turn signals, then less lumens are needed. This is because the Red lens of a brake light filters out all the blue, yellow, green, etc out of white light, but filters nothing from a Red LED. The question now is: What is the percentage of "Red" in the light output of a "White" incandescent bulb?
1156 MINIATURE BULB BA15S BASE - 12.8 Volt 2.1 Amp S8 Single Contact Bayonet (Ba15S) Base, 32 MSCP C-6 Filament Design.
A 1156 bulb typically produces around 1,000 to 1,200 lumens, depending on the specific design and technology used (incandescent, LED, etc.). Incandescent versions tend to be on the lower end of this range, while LED replacements can offer higher lumen outputs for better efficiency. Always check the manufacturer's specifications for the exact lumen output of a particular bulb.
402 lumens initially for 27 Watts in, according to GE at http://genet.gelighting.com/LightProducts/Dispatcher?REQUEST=COMMERCIALSPECPAGE&PRODUCTCODE=26962
1156
Each 32-watt bulb in a 48-inch fluorescent light typically draws around 0.27 amps. Therefore, a two-bulb setup would draw approximately 0.54 amps in total.
1 amp
.63 ampere draw @ 7 volts
1156 miles
It is drawing .06 amps.
To make it more understandable to most anyone,E= Voltage, I= induction, otherwise known as amperage, R= Resistance and W= wattsE=IxR, R= E/I and I=E/R, Watts, that is W= ExISo a 26.9 Watt bulb at 12.8 operating volts will draw 2.1 amps.Assuming you are using this bulb in a automobile with an alternator and a 12Volt sysem your operating voltage will be closer to 14.7 so a little less amperage will be used.Where I=26.9/14.7 I=1.8 , 1.8 amps.Watts is a measure of how much work that is being done. For a given amount of work, a task can be done at twice the voltage using only half the amperage.
Technically if the bulb burns out it doesn't flash at all. The indicator in the car usually does, though, and that's probably what you're asking about. In many cars, the flashing is controlled by a "flasher" unit, which is essentially a small relay. The delay on the flasher depends on the current draw by the bulb. If the bulb burns out, there is no current draw, and the flasher oscillates faster.
A 65 Watt incandescent light bulb should draw 65W/120V = 541.67mA