Each 32-watt bulb in a 48-inch fluorescent light typically draws around 0.27 amps. Therefore, a two-bulb setup would draw approximately 0.54 amps in total.
1 amp
A 65 Watt incandescent light bulb should draw 65W/120V = 541.67mA
A lumen is a measure of how much total light a bulb produces. Incandescent (1156) bulbs spray their light through almost 360 degrees and lamp housings designed for them rely on that. Most LED lamps put all their light out in a narrow cone and work poorly with standard 1156 housings. However, there are LED assemblies that have their light-producing chips arranged around a sphere and they work well in standard housings. The LEDs you see on commercial vehicles are mounted in housings designed for their narrow cone output, that's why they look bright. A standard 1156 bulb puts out about 400 lumens when new. As of January 2010, I haven't found an LED replacement that puts out any more, and most are only 50 lumens or so, not enough for a standard 1156 housing. To confirm the above: From Bosch Automotive Handbook7th ed. a 1156 (BA15S) Stop/Turn 21W bulb puts out 460 lumens. For a 5W Side marker / Tail BA15S it is 50 lumens (strangely low, I know) and 10W Tail light 125 lumens. If replacing with a warm white LED, then that is how many lumens you need to match the brightness (as well as light direction being good). BUT, if using a Red LED for a brake light or an Amber LED for Turn signals, then less lumens are needed. This is because the Red lens of a brake light filters out all the blue, yellow, green, etc out of white light, but filters nothing from a Red LED. The question now is: What is the percentage of "Red" in the light output of a "White" incandescent bulb?
Depends on the size of the LED light and the voltage applied. An example is an LED 24 volt globe light that pulls 8 watts which draw 0.333333 amps. Take an LED 120 volt light bulb draws 12 watts and will pull 0.1 amps. The same bulb at 240 volts wil draw 0.05 amps. it really depends on the watts and voltage applied. An average would be about 0.1 amps.
1156 MINIATURE BULB BA15S BASE - 12.8 Volt 2.1 Amp S8 Single Contact Bayonet (Ba15S) Base, 32 MSCP C-6 Filament Design.
402 lumens initially for 27 Watts in, according to GE at http://genet.gelighting.com/LightProducts/Dispatcher?REQUEST=COMMERCIALSPECPAGE&PRODUCTCODE=26962
1156
.63 ampere draw @ 7 volts
1 amp
Each 32-watt bulb in a 48-inch fluorescent light typically draws around 0.27 amps. Therefore, a two-bulb setup would draw approximately 0.54 amps in total.
1156 miles
It is drawing .06 amps.
Technically if the bulb burns out it doesn't flash at all. The indicator in the car usually does, though, and that's probably what you're asking about. In many cars, the flashing is controlled by a "flasher" unit, which is essentially a small relay. The delay on the flasher depends on the current draw by the bulb. If the bulb burns out, there is no current draw, and the flasher oscillates faster.
To make it more understandable to most anyone,E= Voltage, I= induction, otherwise known as amperage, R= Resistance and W= wattsE=IxR, R= E/I and I=E/R, Watts, that is W= ExISo a 26.9 Watt bulb at 12.8 operating volts will draw 2.1 amps.Assuming you are using this bulb in a automobile with an alternator and a 12Volt sysem your operating voltage will be closer to 14.7 so a little less amperage will be used.Where I=26.9/14.7 I=1.8 , 1.8 amps.Watts is a measure of how much work that is being done. For a given amount of work, a task can be done at twice the voltage using only half the amperage.
A 65 Watt incandescent light bulb should draw 65W/120V = 541.67mA
Five: 1156, 1734, 2601, 3468, 5202.