1 amp
Watts = Amps x Volts x Power Factor If you are talking about a light bulb or similar 60 watt device at 120 VAC the answer is 1/2 amp using standard household voltage and a power factor of 1.
No, 1000VA does not necessarily equal 10 amps. The relationship between VA (volt-amperes) and amps depends on the power factor of the load. For a purely resistive load (like an incandescent light bulb), 1000VA at 120V would be equivalent to approximately 8.3 amps.
At what voltage? Until you tell me the voltage I can't give you an answer. To find out Amps you need to divide the Watts by the Volts. At 120V you have 0.4 amps. At 12V you have 4 amps.
A 65 Watt incandescent light bulb should draw 65W/120V = 541.67mA
The 200 watts on an amplifer would refer to output if it were turned up all the way. This does not tell you how much electricity the amplifier would use. There is some power lost from heat, but we don't know just how much, from the information above.
Watts = Amps x Volts x Power Factor If you are talking about a light bulb or similar 60 watt device at 120 VAC the answer is 1/2 amp using standard household voltage and a power factor of 1.
It's 75/120 and the answer is in amps.
No, 1000VA does not necessarily equal 10 amps. The relationship between VA (volt-amperes) and amps depends on the power factor of the load. For a purely resistive load (like an incandescent light bulb), 1000VA at 120V would be equivalent to approximately 8.3 amps.
You want to know how many amps in that circuit. To do so, divide the Watts by the Volts. in your case it would be 60 watts / 120 volts = 0.5 Amps.
In a series circuit, the current (amps) is constant throughout the circuit. This means that the same amount of current flows through each component connected in series. The current is not divided or reduced as it travels through the circuit.
At what voltage? Until you tell me the voltage I can't give you an answer. To find out Amps you need to divide the Watts by the Volts. At 120V you have 0.4 amps. At 12V you have 4 amps.
The formula you are looking for is I = W/E. Amps = Watts/Volts.
If the bulb's filament is broken, the whole circuit becomes open. If the bulb is in a series circuit or is the only bulb, the electricity would no longer flow. If the bulb is in a parallel circuit, along with other bulbs, then only the blown bulb would go out, and the other bulbs would still work.
The formula you are looking for is Watts = Amps x Volts. Amps = Watts/Volts. This comes to 4 amps load. Minimum size fuse would be 5 amps.
it would be ok in a circuit which didn't need a light bulb.
A 65 Watt incandescent light bulb should draw 65W/120V = 541.67mA
Considering an incandescent bulb and using P=VxI P= Power Watts V= Volts I= Current (amperes) I=P/V I=75Watts/120Volts = 0.625 Amperes (A or Amps) Therefore the current through a 75watt bulb that is connected to a 120volt circuit is 0.625 amps.