Because the voltage is 208 I will assume that it is the 3 phase formula you are looking for. Amps = Kw (430) x 1000/1.73 x Volts (208) x pf. Unless you know the pf use .9 and you won't be to far off in the calculation. Same formula for single phase but don't use 1.73.
In a standard 3 phase system in North America, 7kVa would be equivalent to 19.5 amps on each phase. The equation is: 7kva*1000/208v/1.73=19.45 amps (3 phase)
At 240v single phase it's 70.8 amps. If it runs on 2 wires plus ground, take the voltage rating of the equipment and divide that into the watts to get amps. At 480v 3 phase it's 25.8 amps. At 208v 3 phase it's 47.2 amps. <<>> There are zero amps in 14 kW. A voltage needs to be stated. I = W/E, Amps = Watts/Volts.
400 amps
To convert from kilowatts (kW) to amps in a 3-phase system, we need to know the system voltage. Using the formula: Amps = (kW x 1000) / (√3 x Volts), where √3 is the square root of 3. Assuming a system voltage of 120/208V, the amperage would be approximately 135.1 amps.
Yes but you will not get the full watt rating out of the tank. Watts = amps x volts. Say the tank draws 20 amps. 20A x 240V = 4800 watts. 20A x 208V = 4160 watts. It will take longer to heat your water with less wattage.
no 208v is bigger
1kw=1.25kvaby this relation 75kva=60kwp=1.732*380*I*1I=60000/1.732*380*1I=91AmpsCommentPower factor is irrelevant to this question. You don't need to convert the kV.A rating to kilowatts, simply divide 75 000 V.A by (1.732 x 380). The answer is 114 A.This, of course, assumes that the question refers to a three-phase generator and that 380 V is the line voltage.
There is not enough information provided to answer. KVA is short for "Kilo Volt Amperes". That is, thousands of Volt Amps. In order to determine how many Amperes are flowing, you must know at what voltage it is operating. Amperes = 45,000 ÷ volts Bill Slugg
Clamp the meter around the energized conductor that is connected to the load to be measured and read the amperage off of the dial face of the meter.
There are many types of compressors used for cooling walk in coolers. To answer this question the information has to be taken from the units data plate or the compressor's name plate. Once this information has been found then the breaker and conductor size can be calculated to make the unit operable.
If you have 208 between legs, you have 120 from each leg to neutral (208 divided by 1.73). Assuming a balanced load, this would be 1 KW per leg - 1000 divided by 120 = 8.33 amps per leg. Your question contradicts itself. If you have 208v, the answer above is correct, 8.33 amps. If you have 480v, you have 3.6 amps.
A 500 MCM copper conductor will limit the voltage drop to 3% or less when supplying 350 amps for 150 feet on a 208 volt system.