AWG #10 copper on a 30 amp breaker.
no
It would be at least 250 amps, maybe 300 amps.
The formula for amps is I = W/E. Amps = 40/240 = .17 primary amperage. For the secondary amperage I = W/E. Amps = 40/24 = 1.7 amps.
10A
For a single-phase induction motor, allow 7 amps on a 240 v for a 1-HP motor. Therefore the formula is: current = 7 X HP x 240 / voltage
24.87amps 1 hp=746 watts P=IxV ... (746x8)/240
at 240/50 volt itequates to 4amp
2.3kw
Current (amps) = power (watts) / voltage = 100/240 = 0.42 amps
62.5 amps
3000 divided by 240 approx 13 amps?
To find amps if watts and volts are known, use the formula; watts / volts = amps or 5000 / 240 = 20.83 amps
no
It would be at least 250 amps, maybe 300 amps.
A 6kw load on a 240volt circuit is 25amps.
The equation that you are looking for is Amps = Watts/Volts. There are 6000 watts in 6kW.
12/240, 0.05 amps, maybe about 30% more because of the poor power factor of small transformers.