12.044*10^23 atoms 1.5055*10^23 S8 molecules
1 mole of O atoms, or 0.5 moles of o2 molecules.
The formula of magnesium sulphide is MgS, showing that a formula unit has one atom of each element. The gram atomic mass of magnesium is 24.305 and that of sulphur is 32.06. Therefore, when magnesium and sulphur are present in equal amounts by mass, sulphur is the limiting reactant. 1.0/32.06 or 0.031 moles of sulphur atoms are present. Therefore, the maximum amount of MgS that can result from reaction is 0.031 formula units of MgS. The gram formula mass of MgS is 56.365, so that 0.031 formula units of MgS will have a mass of 1.7 grams, to the justified number of significant digits.
2,88 grams of helium have 3,761.1023 atoms; 16,4 grams of zinc have 1,511.1023 atoms.
Five iron atoms have a mass of 1.3155 x 10-22 grams.
A mole of oxygen atoms has a mass of approximately 16 grams. A mole of O2 has a mass of approximately 32 grams. A mole is 6.02 x 1023 particles and as such a mole of oxygen atoms has only half the mass of a mole of oxygen molecules.
1.659 [grams] / 47.998 [grams / mol] * 6.02214179(30)×1023 [molecules / mole] * 3 [atoms / molecule]. A bunch.
The gram-atomic mass of sulphur is 32 and that of oxygen is 16, to two significant digits. Therefore, the mass of oxygen with the same number of atoms as 64 grams of sulphur can be found from the proportion m/64 = 16/32, or m = 32 grams.
904,000,000,000,000,000,000,000 (9.04 X 10^23) Bromine atoms.
That depends. For the most common form of Iron (Iron-56), there are 56 grams. You may also call 6.02 X 10^23 atoms/molecules a "mole" of atoms/molecules.
30.115*10^23 molecules
Oxygen in the form O2 has a molar mass of 31.9988 gmol-1. In one gram there will be 1/31.9988 mol = 0.0313 mol. One mole of O2 equals 6.022 x 1023 molecules of oxygen, and thereby 1.88 x 1022 molecules of O2 in 1 gram. Since O2 is diatomic there are twice as many atoms as there are molecules and the final calculation to determine the number if atoms is 1.88 x 1022 * 2 = 3.76 x 1022 atoms of oxygen.
no of moles in aspartame =mass/molar mass=1.2/294=0.00408mols no of molecules=0.00408* avagadros no.=0.00408*6.022*10^23=0.02456*10^23 no. of atoms =no.of molecules*2(coz 2 atoms of nitrogen are present)=0.02456*10^23*2
Aluminum sulfide has a molar mass of 150.16 grams per mole. This means there are 0.666 moles present, or 4.01 E23 molecules. Each molecule of Al2S3 has 2 aluminum atoms, so there are 8.02 E23 atoms of aluminum present.
1.88 X 1024 molecules SO3 (1 mole SO3/6.022 X 1023)(80.07 grams/1 mole SO3) = 250 grams sulfur trioxide ===================
2.50 grams C14H18N2O5 (1 mole C14H18N2O5/294.304 grams)(18 moles H/1 mole C14H18N2O5)(6.022 X 1023/1 mole H) = 9.21 X 1022 atoms of aspartame
3.65 grams of water is equal to .203 moles of H2O. This means there is also .203 moles of H2 present, or .408 grams.
1 mole of O atoms, or 0.5 moles of o2 molecules.