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To find the mass of 8.2 x 10²² atoms of N₂I₆, first determine the number of molecules, which is equal to the number of atoms divided by the number of atoms in one molecule of N₂I₆ (which contains 8 atoms). This gives approximately 1.025 x 10²² molecules. The molar mass of N₂I₆ is about 360.8 g/mol. Therefore, the mass in grams can be calculated by multiplying the number of molecules by the molar mass and dividing by Avogadro's number (6.022 x 10²³), resulting in approximately 57.4 grams.

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How many grams are in 8.200 x 1022 molecules of N2I6?

The nitrogen iodide is NI3.


How many grams are in 4.1 X 1022 molecules of N2I6?

To calculate the number of grams in 4.1 x 10^22 molecules of N2I6, you first need to find the molar mass of N2I6. Then, use this molar mass to convert the number of molecules to grams using Avogadro's number and the formula: grams = (number of molecules) / (Avogadro's number) * molar mass.


How many grams are in 8.2 x 10 to the 22 molecules of N2I6?

To convert molecules to grams, you need to use the molar mass of the compound. For N2I6, the molar mass is 539.59 g/mol. First, calculate the number of moles in 8.2 x 10^22 molecules by dividing the number of molecules by Avogadro's number. Then, multiply the number of moles by the molar mass to find the grams.


How many grams of N combine with 7.05x1022 O atoms in N2O5?

The formula N2O5 shows that there are 2/5 as many nitrogen atoms as oxygen atoms in the compound. Therefore, the number of nitrogen atoms required is (2/5)(7.05 X 1022) or 2.82 X 1022 atoms. The gram atomic mass of nitrogen is 14.0067 and, by definition, consists of Avogadro's Number of atoms. Therefore, the mass of nitrogen required to react with the specified amount of oxygen to produce the specified compound is 14.0067 [(2.82 X 1022)/(6.022 X 1023] or 0.656 grams of nitrogen, to the justified number of significant digits.


How many grams of lead is needed to equal the number of atoms contained in 10 grams of tin?

Let us do this in two parts for clarity. Find atoms in tin first. 10 grams tin (1 mole Sn/118.7 grams)(6.022 X 1023/1 mole Sn) = 5.07 X 1022 atoms of tin ----------------------------------- 5.07 X 1022 atoms (1 mole Pb/6.022 X 1023)(207.2 grams/1 mole Pb) = 17 grams of lead ------------------------------ I can see two other ways to do the conversion string, one longer and one much shorter. See if you can find them.

Related Questions

How many grams are in 8.200 x 1022 molecules of N2I6?

The nitrogen iodide is NI3.


How many grams are in 4.1 X 1022 molecules of N2I6?

To calculate the number of grams in 4.1 x 10^22 molecules of N2I6, you first need to find the molar mass of N2I6. Then, use this molar mass to convert the number of molecules to grams using Avogadro's number and the formula: grams = (number of molecules) / (Avogadro's number) * molar mass.


How many grams are in 8.2x10to the 22 atoms of N2I6?

To calculate the number of grams in 8.2x10^22 molecules of N2I6, you would need to determine the molar mass of N2I6. Once you have the molar mass, you can use it to convert the number of molecules to grams using Avogadro's number and the formula: mass = (number of molecules / Avogadro's number) x molar mass.


How many grams do 4.4 x 1022 atoms of potassium weigh. answer in units of grams?

The mass is 2.86 grams but the weight will be 0.028 Newtons.


How many na atoms can be produced Of 3.5g?

3.5 grams Na (1 mole Na/22.99 grams)(6.022 X 1023/1 mole Na) = 9.2 X 1022 atoms of sodium ===================


How many atoms of sulfur are in 3.86 g?

For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023.3.86 grams S / (32.1 grams) × (6.02 × 1023 atoms) = 7.24 × 1022 atoms


What is the number of carbon hydrogen and oxygen atoms in 3.00 grams of glucose?

The first step is calculating how many molecules of glucose are in 3.00 grams. To do this, you need the molecular mass of the compound (glucose), which is found by adding up the weights of the elements involved in C6H12O6. C6: 12.0 × 6 = 72.0 H12: 1.0 × 12 = 12.0 O6: 16.0 × 6 = 96.0 72.0 + 12.0 + 96.0 = 180.0 grams/mol With this and Avogadro's constant (6.02 × 1023), we can then convert 3.00 grams of glucose to number of molecules. 3.00 grams ÷ 180.0 grams/mol × (6.02 × 1023) = 1.00 × 1022 molecules of glucose So now we know how many molecules of glucose there are. We also know from the formula that in one molecule of glucose, there are 6 atoms of carbon, 12 atoms of hydrogen, and 6 atoms of oxygen. Number of atoms in one molecule × number of molecules = number of atoms in given amount 6 × (1.00 × 1022) = 6.00 × 1022 atoms of carbon 12 × (1.00 × 1022) = 1.20 × 1023 atoms of hydrogen 6 × (1.00 × 1022) = 6.00 × 1022 atoms of oxygen


How many grams are there in 3.3 x 1023 molecules of N2I6?

divide the amount of particles given in the question by avagado's number to get the amount in moles. 3.01 x 1023 / 6.022 x 1023 which is about 0.5 moles. them multiply the amount of moles by the mass of Nitrogen to get it in grams. 0.5 x 14 = 7g


What is the mass of 5.0g of Fe how many atoms are present?

For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023.5.0 grams Fe / (55.9 grams) × (6.02 × 1023 atoms) = 5.38 × 1022 atoms


How many atoms of gold are in 5 grams of gold?

Atomic mass of Ag: 107.9 grams5.00 grams × (6.02 × 1023 atoms) / (107.9 grams) = 2.79 × 1022 atoms Ag


How many oxygen atoms are in 0.87 g of water?

0.87 grams water (1 mole H2O/18.016 grams)(1 mole O/1 mole H2O)(6.022 X 1023/1 mole O) = 2.9 X 1022 atoms of oxygen --------------------------------------


How many grams are in 8.2 x 10 to the 22 molecules of N2I6?

To convert molecules to grams, you need to use the molar mass of the compound. For N2I6, the molar mass is 539.59 g/mol. First, calculate the number of moles in 8.2 x 10^22 molecules by dividing the number of molecules by Avogadro's number. Then, multiply the number of moles by the molar mass to find the grams.