Quite a few!
8.2 X 10^22 atoms of N2I6 (1 mole N2I6/6.022 X 10^23)(789.42 grams/1 mole N2I6)
= 107 grams of N2I6
(Would have been peanuts without all that iodine! )
107.5 g N2I6
divide the amount of particles given in the question by avagado's number to get the amount in moles. 3.01 x 1023 / 6.022 x 1023 which is about 0.5 moles. them multiply the amount of moles by the mass of Nitrogen to get it in grams. 0.5 x 14 = 7g
25,1 grams sulfur contain 4,7147765.10e23 atoms.
The answer is 9,17233.1023 atoms.
3,45 grams of H2O contain 1,154.10e23 oxygen atoms.
106.7 grams
107.5 g N2I6
The nitrogen iodide is NI3.
divide the amount of particles given in the question by avagado's number to get the amount in moles. 3.01 x 1023 / 6.022 x 1023 which is about 0.5 moles. them multiply the amount of moles by the mass of Nitrogen to get it in grams. 0.5 x 14 = 7g
25,1 grams sulfur contain 4,7147765.10e23 atoms.
The answer is 28,0987.1023 atoms.
The answer is 9,17233.1023 atoms.
1,25 grams of CH4 contain 0,156696.10e23 atoms.
738 grams iron are equivalent to:- 12,626 moles- 76.10e23 atoms
3,45 grams of H2O contain 1,154.10e23 oxygen atoms.
45,0 grams of hydrogen gas have 135,5.10e23 atoms.
Atomic mass of Ag: 107.9 grams5.00 grams × (6.02 × 1023 atoms) / (107.9 grams) = 2.79 × 1022 atoms Ag