How many grams are there in 3.3 x 1023 molecules of N2I6?

Answer 1

divide the amount of particles given in the question by avagado's number to get the amount in moles.

3.01 x 1023 / 6.022 x 1023

which is about 0.5 moles.

them multiply the amount of moles by the mass of Nitrogen to get it in grams.

0.5 x 14 = 7g

Answer 2

1mole N2I6 = 789.44022g N2I6

1mole N2I6 = 6.022 x 1023 molecules N2I6

1) Convert molecules to moles.

3.3 x 1023 molecules N2I6 x (1mol N2I6/6.022 x 1023 molecules N2I6) = 0.55mol* N2I6

* Rounded to two significant figures.

2) Convert moles to mass in grams.

0.55mol N2I6 x (789.44022g N2I6/1mol N2I6 = 430g* N2I6

*Rounded to two significant figures.

Answer 3

A total of 8.37*1023 molecules of N2 are in (8.37*1023) / (6.022*1023) = 1.39 moles

Answer 4

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Answer 5

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