38 grams oxygen gas (1 mole O2/32 grams)(6.022 X 1023/1 mole O2)
= 7.2 X 1023 molecules of oxygen gas
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6H2 + 6O2 ---> 6H2O + 3O2 This reaction leave excess unreacted oxygen behind.
To find the number of oxygen atoms in 3.120 grams, we need to first calculate the number of moles using the molar mass of oxygen gas. The molar mass of oxygen gas is 32 g/mol. So, 3.120 grams is equal to 0.0975 moles. Each mole of oxygen gas contains 2 oxygen atoms, so there are 0.195 moles of oxygen atoms in 3.120 grams. Finally, using Avogadro's number (6.022 x 10^23), we find that 1.17 x 10^23 oxygen atoms are present in 3.120 grams of oxygen gas.
To determine the amount of gas needed to react with 348.5 grams of oxygen, you need to know the balanced chemical equation of the reaction. Then, use the stoichiometry of the reaction to calculate the amount of gas required based on the molar ratio between the gas and oxygen in the reaction.
To determine the number of molecules in 5.60 L of oxygen gas, we first need to convert the volume to moles using the ideal gas law. Then, we use Avogadro's number (6.022 x 10^23) to convert moles to molecules. The final answer will depend on the temperature and pressure of the oxygen gas.
four moles. Approximately. Oxygen has a molecular weight of 16.0 grams per mole so 64 grams divided by 16.0 grams per mole is four moles.
For what purpose?
It is not measured in grams but PPM because it is a gas.
6H2 + 6O2 ---> 6H2O + 3O2 This reaction leave excess unreacted oxygen behind.
To find the number of oxygen atoms in 3.120 grams, we need to first calculate the number of moles using the molar mass of oxygen gas. The molar mass of oxygen gas is 32 g/mol. So, 3.120 grams is equal to 0.0975 moles. Each mole of oxygen gas contains 2 oxygen atoms, so there are 0.195 moles of oxygen atoms in 3.120 grams. Finally, using Avogadro's number (6.022 x 10^23), we find that 1.17 x 10^23 oxygen atoms are present in 3.120 grams of oxygen gas.
6,5 moles oxygen equals 208 g.
15.994 grams/mol, but it can rounded to 15.99 or 16.0 g/mol.
That depends on the fuel. Natural gas, methane, needs 2 molecules of oxygen, but gasoline, octane, needs 17 molecules of oxygen.
The answer is 2 moles.
Assuming you mean oxygen gas, the number of molecules can be found by first finding the number of moles = mass of oxygen (4g) / Molecular mass of oxygen gas (32 g mol-1) This tells us there is 0.125 mol of oxygen gas present. The number of molecules present is given by the number of moles x the avogadro constant (6.022x10^23) So the number of oxygen gas molecules present is equal to 0.125 x 6.022x10^23 = 7.5275x10^22 molecules
To determine the amount of gas needed to react with 348.5 grams of oxygen, you need to know the balanced chemical equation of the reaction. Then, use the stoichiometry of the reaction to calculate the amount of gas required based on the molar ratio between the gas and oxygen in the reaction.
To determine the number of molecules in 5.60 L of oxygen gas, we first need to convert the volume to moles using the ideal gas law. Then, we use Avogadro's number (6.022 x 10^23) to convert moles to molecules. The final answer will depend on the temperature and pressure of the oxygen gas.
One is produced