well... the whole process of getting it is quite simple:
first you multiply the mass of boron by 1 divided by the moloar mass which in this case it is 10
10.81 * (1/10) or 10.81/10 =1.081
second, you multiply the result by Avogadro's number or 6.02*1023
1.081 * (6.02*1023) = 6.5*1023
after this your finished. this is the process to finding the number of atoms to any element. hopes this helps!
This cannot be possible. Atoms cannot be divided or separated, meaning there cannot be a part of an atom. Either you have 6 atoms or 7 atoms, etc. You can't however, have 6.5 atoms or 9.63 atoms. When expressing a number of atoms that has a decimal, usually it will be due to scientific notation, which requires it.
2
1.00*10-7 moles of boron is how many grams is this
There are 4 boron atoms in a molecule of borax, which has the chemical formula Na2B4O7·10H2O.
there are 5 electrons in boron atoms.
This cannot be possible. Atoms cannot be divided or separated, meaning there cannot be a part of an atom. Either you have 6 atoms or 7 atoms, etc. You can't however, have 6.5 atoms or 9.63 atoms. When expressing a number of atoms that has a decimal, usually it will be due to scientific notation, which requires it.
2
1.00*10-7 moles of boron is how many grams is this
There are 4 boron atoms in a molecule of borax, which has the chemical formula Na2B4O7·10H2O.
there are 5 electrons in boron atoms.
There is one boron atom in one molecule of BF3.
Boron dioxide would have formula BO2, with a total of three atoms, BUT this is NOT a possible compound.B2O3, with 5 atoms, is called boron trioxide (or diboron trioxide, boron oxide, boron sesquioxide, boric oxide alternatively).
There is 13 isotopes in the element boron. xD
Boron has five protons.The element boron has 5 protons.5
Boron has 3 valence electrons.
None, as pure Aluminium is an element which contains only atoms of Aluminium and nothing else.
Boron atoms have 5 protons. You can derive this from the periodic table because the atomic number is the amount of protons the nucleus of an atom contains.