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This cannot be possible. Atoms cannot be divided or separated, meaning there cannot be a part of an atom. Either you have 6 atoms or 7 atoms, etc. You can't however, have 6.5 atoms or 9.63 atoms. When expressing a number of atoms that has a decimal, usually it will be due to scientific notation, which requires it.
What else can I help you with?
What would you multiply atoms of boron by to get the units grams of boron?
There is no direct relationship between atoms of boronand grams of boron. Use Avogadro's number to convert atoms to moles, and the atomic mass to convert moles to grams.Since you are converting from atoms B, this goes in the denominator (on the bottom) of the first factor. You want to end up in units of grams of B, so this goes in the numerator (on the top) of the last factor.atoms B1.00 mole B10.8 gram = g B6.02E+23 atom B1.00 mole BNote that the units atoms boron "cancel out" in the first factor and you are left in units of moles. Moles cancel outin the second factor and the final units are grams boron.
What approximate mass would a sample of naturally occurring boron (B) that contains 1 x 106 atoms of boron have?
The molar mass of boron is approximately 10.81 g/mol. To find the mass of 1 x 10^6 atoms of boron, divide the number of atoms by Avogadro's number to get the number of moles, then multiply by the molar mass of boron. Therefore, the mass of 1 x 10^6 boron atoms would be approximately 1 x 10^-5 grams.
How many grams of fluorine are contained in 5 molecules of boron trifluoride?
To calculate the number of grams of fluorine in 5 molecules of boron trifluoride, you need to first determine the molar mass of boron trifluoride (BF3). Boron trifluoride has one boron atom and three fluorine atoms, so the molar mass is ~ 67.8 g/mol. Since each molecule of boron trifluoride contains three fluorine atoms, the total mass of fluorine in 5 molecules would be 3 times the molar mass of fluorine (approximately 19.0 g/mol) times 5.
What approximate mass would a sample of naturally occurring boron (B) that contains 1 and times 106 atoms of boron have?
The molar mass of boron is approximately 10.81 g/mol. To calculate the mass of 1 x 10^6 boron atoms, you divide 6.022 x 10^23 (Avogadro's number) by 1 x 10^6 to find the number of moles, which equals 0.001673 moles. Multiply this by the molar mass of boron to get approximately 0.0181 grams.
How many atoms are in 20 grams of the element boron?
well... the whole process of getting it is quite simple: first you multiply the mass of boron by 1 divided by the moloar mass which in this case it is 10 10.81 * (1/10) or 10.81/10 =1.081 second, you multiply the result by Avogadro's number or 6.02*1023 1.081 * (6.02*1023) = 6.5*1023 after this your finished. this is the process to finding the number of atoms to any element. hopes this helps!
What is the mass of a boron sample which contains 585 moles of b atoms?
Each mole of boron atoms has a mass of 10.811 grams, as indicated by the gram atomic mass or weight of boron. Therefore, 585 moles has a mass of about 6.32 X 103 grams, to the same number of significant digits as 585.
A 5.00 gram sample of BF3 contains how many grams of boron?
Boron (B) has a molar mass of approximately 10.81 g/mol. In BF3, there is 1 boron atom. To calculate the mass of boron in 5.00 grams of BF3, you would use the molar mass of boron to find that it contains approximately 1.46 grams of boron.
What would you multiply atoms of boron by to get the units grams of boron?
There is no direct relationship between atoms of boronand grams of boron. Use Avogadro's number to convert atoms to moles, and the atomic mass to convert moles to grams.Since you are converting from atoms B, this goes in the denominator (on the bottom) of the first factor. You want to end up in units of grams of B, so this goes in the numerator (on the top) of the last factor.atoms B1.00 mole B10.8 gram = g B6.02E+23 atom B1.00 mole BNote that the units atoms boron "cancel out" in the first factor and you are left in units of moles. Moles cancel outin the second factor and the final units are grams boron.
What approximate mass would a sample of naturally occurring boron (B) that contains 1 x 106 atoms of boron have?
The molar mass of boron is approximately 10.81 g/mol. To find the mass of 1 x 10^6 atoms of boron, divide the number of atoms by Avogadro's number to get the number of moles, then multiply by the molar mass of boron. Therefore, the mass of 1 x 10^6 boron atoms would be approximately 1 x 10^-5 grams.
How many grams of fluorine are contained in 5 molecules of boron trifluoride?
To calculate the number of grams of fluorine in 5 molecules of boron trifluoride, you need to first determine the molar mass of boron trifluoride (BF3). Boron trifluoride has one boron atom and three fluorine atoms, so the molar mass is ~ 67.8 g/mol. Since each molecule of boron trifluoride contains three fluorine atoms, the total mass of fluorine in 5 molecules would be 3 times the molar mass of fluorine (approximately 19.0 g/mol) times 5.
What approximate mass would a sample of naturally occurring boron (B) that contains 1 and times 106 atoms of boron have?
The molar mass of boron is approximately 10.81 g/mol. To calculate the mass of 1 x 10^6 boron atoms, you divide 6.022 x 10^23 (Avogadro's number) by 1 x 10^6 to find the number of moles, which equals 0.001673 moles. Multiply this by the molar mass of boron to get approximately 0.0181 grams.
How many atoms are in 20 grams of the element boron?
well... the whole process of getting it is quite simple: first you multiply the mass of boron by 1 divided by the moloar mass which in this case it is 10 10.81 * (1/10) or 10.81/10 =1.081 second, you multiply the result by Avogadro's number or 6.02*1023 1.081 * (6.02*1023) = 6.5*1023 after this your finished. this is the process to finding the number of atoms to any element. hopes this helps!
How many grams are in one mole of boron?
1.00*10-7 moles of boron is how many grams is this
What does 16.0 grams of oxygen contains?
1 mole of O atoms, or 0.5 moles of o2 molecules.
What is the density of boron?
Boron has a density of 2.34 grams per cubic centimeter. A link is provided. It also has a mass of 10.811 grams.
Every drop of seawater contains approximately how many gold atoms?
Every drop of seawater contains around 0.12 billion gold atoms.
How many grams of boron tribromide must be weighed out to get a sample of boron tribromide that contains 11.8 g of bromine?
The atomic mass of boron is 10.811 while that of bromine is 79.904. Thus the ratio of the mass of bromine to the total mass of boron tribromide must be: 3(79.904)/[3(79.904) + 10.811] = 0.9568. The required mass of BBr3 thus is 11.8/0.9568 = 12.3 g, to the justified number of significant digits.
