0.0979 g
The molar mass of boron trifluoride (BF3) is 67.81 g/mol. Since boron makes up 1/3 of the molecular formula, the molar mass of boron is 67.81/3 = 22.60 g/mol. Therefore, in a 5.00 g sample of BF3, the amount of boron present would be (5.00g / 67.81 g/mol) * 22.60 g/mol = 1.67 grams.
Boron density: 2,08 g/cm3 Water density: 1 g/cm3
To work this out you need to know the atomic weight of calcium and Avogadros number, which is the number of atoms in a gram atom. Calcium has an atomic weight of 40.078. Therefore a gram ato is 40.078 grams which contains 6.02214129(27)×1023 atoms. 1g of calcium contains 6.02214129(27)×1023 / 40.078 1.502 X 1022
To calculate the number of moles of ammonium ions in a 22.5 gram sample of ammonium carbonate, you need to first determine the molar mass of ammonium carbonate. Then, divide the given mass by the molar mass to find the number of moles. After that, since there are 2 ammonium ions in one molecule of ammonium carbonate, you will need to multiply the result by 2 to determine the number of moles of ammonium ions.
moles = mass/Mr moles = 100/(23+16+1) moles of NaOH = 2.5mol
Each mole of boron atoms has a mass of 10.811 grams, as indicated by the gram atomic mass or weight of boron. Therefore, 585 moles has a mass of about 6.32 X 103 grams, to the same number of significant digits as 585.
The molar mass of boron trifluoride (BF3) is 67.81 g/mol. Since boron makes up 1/3 of the molecular formula, the molar mass of boron is 67.81/3 = 22.60 g/mol. Therefore, in a 5.00 g sample of BF3, the amount of boron present would be (5.00g / 67.81 g/mol) * 22.60 g/mol = 1.67 grams.
A 5 gram tablet contains 5 grams.
Since each molecule of sodium chloride contains one sodium atom, the mass of the sodium in a 150 gram sample of sodium chloride would be the same as the mass of the sample itself, which is 150 grams.
There are 1.5 moles of water molecules in a 27 gram sample of water. This is calculated by dividing the mass of the sample (27 grams) by the molar mass of water (18 grams/mol).
12
Potassium nitrate has a molar mass of 101.1 g/mol, with one potassium atom accounting for 39.1 g/mol. Using a simple stoichiometric calculation, it can be determined that a 42.7 g sample of potassium nitrate contains approximately 16.64 grams of potassium.
2.66666666666667 grams
There are approximately 6 x 10^22 atoms in a 12.0 gram sample of sodium.
How many calories are in a food which has 10 grams of protein, 4 grams of fat, and 20 grams of carbohydrate
The gram contains
The mineral with a mass of 54 grams could be quartz, feldspar, or calcite. Minerals have varying densities, so a 54-gram sample of one mineral may occupy a different volume than a 54-gram sample of another mineral.