16.5
Quite a few! 427.4 grams KNO3 (1 mole KNO3/101.11 grams)(6.022 X 1023/1 mole KNO3) = 2.546 X 1024 molecules of potassium nitrate -----------------------------------------------------------
To determine which substance contains the largest number of moles, you need to divide the given mass of each substance by its molar mass to find the number of moles. The substance with the largest number of moles will have the smallest molar mass. In this case, Neon (Ne) has the smallest molar mass, so it contains the largest number of moles.
The amount of crystals formed will depend on how much potassium nitrate was dissolved in the solution to begin with. As the solution cools from 60°C to 30°C, potassium nitrate will begin to crystallize out of the solution. The exact amount of crystals can be determined by calculating the solubility of potassium nitrate at 30°C and comparing it to the initial concentration in the solution.
To prepare one normal solution of potassium nitrate, you would dissolve 101.1 grams of potassium nitrate in enough water to make 1 liter of solution. This solution will have a concentration of 1 mole per liter, which is considered a normal solution. Make sure to use a balance to accurately measure the mass of potassium nitrate and a volumetric flask to ensure a final volume of 1 liter.
The molar mass of KHCO3 is 100.12 g/mol. This means that 100 grams of KHCO3 contains 39.1 grams of potassium (K) ions.
65 degrees of potassium nitrate will remain in water while only 35% of water will still be detectable in the solute potassium nitrate
Based on the ratio of 8 grams of radioactive potassium-40 to 56 grams of its nonradioactive decay products, we can infer that half of the initial potassium-40 has decayed. Since the half-life of potassium-40 is about 1.25 billion years, we can estimate the age of the sample to be around 1.25 billion years.
530,3 g potassium iodide are needed.
Quite a few! 427.4 grams KNO3 (1 mole KNO3/101.11 grams)(6.022 X 1023/1 mole KNO3) = 2.546 X 1024 molecules of potassium nitrate -----------------------------------------------------------
At 313K, the solubility of potassium nitrate in water is approximately 62g/100g of water. To form a saturated solution in 50g of water, you would need roughly 31g of potassium nitrate.
The gram atomic mass of gold is 196.967 and that of potassium is 39.0983. Therefore, equal numbers of atoms of potassium are supplied by 39.0983/196.967 the mass of potassium compared with gold. 5 X 9.85 = 49.25. This contains the same number of gold atoms as 49.25(39.0983/196.967) or 9.78 grams of potassium contains of potassium atoms, to the justified number of significant digits (limited by the number "9.85", assuming that "5" is intended to be exact.)
Potassium has atomic number 39.1.Amount of K in 284g sample = 284/39.1 = 7.26molThere are 7.26 moles of potassium in a 284g sample.
To determine which substance contains the largest number of moles, you need to divide the given mass of each substance by its molar mass to find the number of moles. The substance with the largest number of moles will have the smallest molar mass. In this case, Neon (Ne) has the smallest molar mass, so it contains the largest number of moles.
The solubility of poassium nitrate in water at 20 oC is 616 g/L.
The amount of crystals formed will depend on how much potassium nitrate was dissolved in the solution to begin with. As the solution cools from 60°C to 30°C, potassium nitrate will begin to crystallize out of the solution. The exact amount of crystals can be determined by calculating the solubility of potassium nitrate at 30°C and comparing it to the initial concentration in the solution.
To prepare one normal solution of potassium nitrate, you would dissolve 101.1 grams of potassium nitrate in enough water to make 1 liter of solution. This solution will have a concentration of 1 mole per liter, which is considered a normal solution. Make sure to use a balance to accurately measure the mass of potassium nitrate and a volumetric flask to ensure a final volume of 1 liter.
The molar mass of KHCO3 is 100.12 g/mol. This means that 100 grams of KHCO3 contains 39.1 grams of potassium (K) ions.