Quite a few!
427.4 grams KNO3 (1 mole KNO3/101.11 grams)(6.022 X 1023/1 mole KNO3)
= 2.546 X 1024 molecules of potassium nitrate
-----------------------------------------------------------
16.5
30.115*10^23 molecules
the solubility of potassium nitrate in 70 degreesCelsius water is about 134 g KNO3 per 100 g water
A 42.7 gram sample of potassium nitrate (KNO3) contains how many grams of potassium?
6.023 x 1023 molecules of iron(III) nitrate weigh 241.86 g So, 4.80 x 1023 molecules will weigh 192.75 g
16.5
530,3 g potassium iodide are needed.
More than 45,5 g KNO3.
Well, because you have 65g of AgNO3, you have .3826 moles of silver nitrate. This is found by dividing the number of grams you have by the molar mass of silver nitrate (169.9g/mol). Once you know how many moles there are you can then multiply by Avogodro's number (6.022x1023) to obtain the number of molecules. In this case it is 2.304x1023 molecules.
Well, because you have 65g of AgNO3, you have .3826 moles of silver nitrate. This is found by dividing the number of grams you have by the molar mass of silver nitrate (169.9g/mol). Once you know how many moles there are you can then multiply by Avogodro's number (6.022x1023) to obtain the number of molecules. In this case it is 2.304x1023 molecules.
65 degrees of potassium nitrate will remain in water while only 35% of water will still be detectable in the solute potassium nitrate
30.115*10^23 molecules
The solubility of poassium nitrate in water at 20 oC is 616 g/L.
A 42.7 gram sample of potassium nitrate (KNO3) contains how many grams of potassium?
the solubility of potassium nitrate in 70 degreesCelsius water is about 134 g KNO3 per 100 g water
6.023 x 1023 molecules of iron(III) nitrate weigh 241.86 g So, 4.80 x 1023 molecules will weigh 192.75 g
how many moles are there in 56.0 grams of silver nitrate?