hicke
0.0979 g
A 22.5 gram sample of ammonium carbonate contains 4.5 moles of ammonium ions.
it has 6 gram of copper
To work this out you need to know the atomic weight of calcium and Avogadros number, which is the number of atoms in a gram atom. Calcium has an atomic weight of 40.078. Therefore a gram ato is 40.078 grams which contains 6.02214129(27)×1023 atoms. 1g of calcium contains 6.02214129(27)×1023 / 40.078 1.502 X 1022
Gram is a unit of mass. Just look at the number that comes before 'gram'. That's the mass, in grams.
0.0979 g
Each mole of boron atoms has a mass of 10.811 grams, as indicated by the gram atomic mass or weight of boron. Therefore, 585 moles has a mass of about 6.32 X 103 grams, to the same number of significant digits as 585.
16.5
A 42.7 gram sample of potassium nitrate (KNO3) contains how many grams of potassium?
Boron costs about $5 per gram
12
A 22.5 gram sample of ammonium carbonate contains 4.5 moles of ammonium ions.
2.66666666666667 grams
Boron is currently $5 per gram, or around $2, 268 per pound.Wow! If you're doing experiments, may I suggest buying a few grams? :D
The gram contains
A one 443 gram can of refried beans contains 24 grams of protein. One cup contains 12 grams of protein.
A sample of Se weighs 20.5 grams. Will a sample of V that contains the same number of atoms weigh more or less than 20.5 grams? (more, less): _______Calculate the mass of a sample of V that contains the same number of atoms. _______ grams of VAnswer:Since the atomic weight of V is smaller than the atomic weight of Se, each atom will have a smallermass, and the sample will weigh less.Since the same number of moles will contain the same number of atoms, regardless of the element, it is only necessary to find the number of moles of Se in the 20.5 gram sample, and then to find the mass of the same number of moles of V.The atomic weight of Se is 79.0 g/mol1. Convert grams of Se to moles of Se:moles Se= 20.5 g Se1 mol = 0.260 mol Se79.0 gMultiply by moles per gram. Grams cancel out.The atomic weight of V is 50.9 g/mol2. To convert 0.260 moles of V to grams of V:grams V = 0.260 mol V50.9 g = 13.2 g V1 molMultiply by grams per mole. Moles cancel out.