3.011 x 1023 atoms of carbon will weigh about 6 grams One mole of carbon atoms weighs 12.011 grams, and there are 6.022 x 1023 atoms in a moles. So you have half as many atoms, so the mass would be half as much or 6.0055 grams to be precise.
72.0 grams Carbon (1 mole C/12.01 grams)(6.022 X 10^23/1 mole C) = 3.61 X 10^24 atoms of carbon
3.50 grams carbon 12 (1 mole C(12)/12.0 grams)(6.022 X 10^23/1 mole C(12)) = 1.76 X 10^23 atoms
77.28 grams C2H6 (1 mole C2H6/30.068 grams)(2 mole C/1 mole C2H6)(6.022 X 10^23/1 mole C) = 3.096 X 10^24 atoms of carbon
10 pounds C12H22O11 (454 grams/1 pound)(1 mole C12H22O11/342.296 grams)(12 mole C/1 mole C12H22O11)(6.022 X 1023/1 mole C) = 9.6 X 1025 atoms of carbon =====================
17 grams carbon (1 mole C/12.01 grams)(6.022 X 1023/1 mole C) = 8.5 X 1023 atoms of carbon =====================
31.8 grams carbon (1 mole C/12.01 grams)(6.022 X 1023/1 mole C)= 1.59 X 1024 atoms of carbon===================
Atomic mass of carbon: 12.0 grams1.90 grams × (6.02 × 1023 atoms) / (12.0 grams) = 9.53 × 1022 atoms C
1.7 grams * (1mole/ 12.011 grams) * (6.023x 10^23 atoms/ 1 mole) =8.525 * 10^ 22 atoms carbon round to 2 sig. figs
So, there are approximately 8.74 × 1 0 24 8.74×10 24 hydrogen atoms in 800 grams of C 3 H 8 C 3 H 8 .
3.011 x 1023 atoms of carbon will weigh about 6 grams One mole of carbon atoms weighs 12.011 grams, and there are 6.022 x 1023 atoms in a moles. So you have half as many atoms, so the mass would be half as much or 6.0055 grams to be precise.
0.5 carat carbon (0.2 grams/1 carat)(1 mole C/12.01 grams)(6.022 X 1023/1 mole C) = 5.0 X 1021 atoms of carbon ===================
Not that much!! 4350000 atoms Carbon (1 mole C/6.022 X 10^23)(12.01 grams/1 mole C) = 8.675 X 10^-17 grams
2.6 grams graphite ( just carbon ) (1 mole C/12.01 grams)(6.022 X 1023/1 mole C) = 1.3 X 1023 atoms of carbon in that mass graphite ================================
For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023.1000 grams C / (12.0 grams) × (6.02 × 1023 atoms) = 5.02 × 1025 atoms
Carbon is equal to 12.01 grams. 1.) determine how many moles of carbon are there in the mass given. Just use the conversion method. In this case, 12.011 g C x ( mol C / 12.01 g C) = 1 mole of C 2.)Acc to Avogadro's number, one mole of any element is equal to 6.02 x 10^23 atoms. there is one mole of Carbon is 12.01 grams, therefore, it takes 6.01x10^23 atoms.
That is about the mole definition of Avogadro's number, so. 6.022 X 10^23 atoms of carbon