The number of atoms is 101,341.10e23.
To produce potassium nitride (K₃N), the balanced chemical equation is 6 K + N₂ → 2 K₃N. This indicates that 6 moles of potassium are required to produce 2 moles of potassium nitride. Therefore, to produce 2.0 moles of K₃N, you would need 6 moles of potassium.
The answer is 12, 044 280.1023 atoms.
Since molecules of potassium contain only single potassium atoms, molecules of iodine contain two atoms, and moles of potassium iodide contain one atom of each element, 2.5 moles of iodine are needed to react completely with 5 moles of potassium.
To find the number of moles of potassium, we need to first determine the molar quantity of potassium atoms in one mole. A mole is equivalent to Avogadro's number, which is 6.022e23 atoms per mole. So, 7.85e23 potassium atoms would be approximately 1.304 moles of potassium.
Four (4) mol of potassium are represented.
To find the number of potassium atoms in a sample of K2Cr2O7, you first need to calculate the number of moles of K2Cr2O7 using its molar mass. Then, you can determine the number of moles of potassium atoms since there are 2 potassium atoms in each molecule of K2Cr2O7. Finally, use Avogadro's number (6.022 x 10^23) to convert the number of moles of potassium atoms to the actual number of atoms.
7,68 grams of calcium nitride is equal to 0,052 moles.
In potassium dichromate (K2Cr2O7), there are 7 oxygen atoms per molecule. Therefore, two moles of K2Cr2O7 would contain 14 moles of oxygen atoms. Each mole of oxygen atoms has a molar mass of approximately 16 grams, so there would be 224 grams of oxygen in two moles of potassium dichromate.
In 2 moles of potassium dichromate, there are 16 moles of oxygen atoms (from the two oxygen atoms in each formula unit). The molar mass of oxygen is 16 g/mol, so in 2 moles of potassium dichromate, there are 32 grams of oxygen.
Barium nitride is Ba3N2 (from the rules of ionic bonding). Its molar mass is 439 grams/mole (from the periodic table), so 18.8 grams of it is 0.0428 moles (by algebraic direct proportion). Multiply this by Avogadro's number (6.02x1023; the number of particles in 1 mole) and you get 2.58x1022 formula units of barium nitride, and there are 2 nitrogen atoms per formula unit, so double it to 5.16x1022 atoms of nitrogen.
3KNO3, so 9 oxygen atoms.
0.3 moles K (6.022 X 10^23/1mol K) = 1.8 X 10^23 atoms of K