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The number of atoms is 101,341.10e23.

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How many atoms of potassium need to react with nitrogen in order to produce 2.0 moles of potassium nitride?

To produce potassium nitride (K₃N), the balanced chemical equation is 6 K + N₂ → 2 K₃N. This indicates that 6 moles of potassium are required to produce 2 moles of potassium nitride. Therefore, to produce 2.0 moles of K₃N, you would need 6 moles of potassium.


How many atoms of potassium make up two moles?

The answer is 12, 044 280.1023 atoms.


How many moles of iodine are needed to react with 5 moles of potassium to create potassium iodide?

Since molecules of potassium contain only single potassium atoms, molecules of iodine contain two atoms, and moles of potassium iodide contain one atom of each element, 2.5 moles of iodine are needed to react completely with 5 moles of potassium.


How many mol of potassium are represented by 7.85e23 potassium atoms?

To find the number of moles of potassium, we need to first determine the molar quantity of potassium atoms in one mole. A mole is equivalent to Avogadro's number, which is 6.022e23 atoms per mole. So, 7.85e23 potassium atoms would be approximately 1.304 moles of potassium.


How many mol of potassium are represented by 7.85 x 10 23 potassium atoms?

Four (4) mol of potassium are represented.


How many potassium atoms are there in a sample of K2Cr2O7 having a mass of 24.43 g?

To find the number of potassium atoms in a sample of K2Cr2O7, you first need to calculate the number of moles of K2Cr2O7 using its molar mass. Then, you can determine the number of moles of potassium atoms since there are 2 potassium atoms in each molecule of K2Cr2O7. Finally, use Avogadro's number (6.022 x 10^23) to convert the number of moles of potassium atoms to the actual number of atoms.


How many moles present in 7.68 grams of calcium nitride?

7,68 grams of calcium nitride is equal to 0,052 moles.


How many grams of oxygen wil be in two moles of potassium dichromate?

In potassium dichromate (K2Cr2O7), there are 7 oxygen atoms per molecule. Therefore, two moles of K2Cr2O7 would contain 14 moles of oxygen atoms. Each mole of oxygen atoms has a molar mass of approximately 16 grams, so there would be 224 grams of oxygen in two moles of potassium dichromate.


He formula for potassium dichromate is KËÃCrËÃOËÈ How many grams of oxygen will be in 2 moles of potassium dichromate?

In 2 moles of potassium dichromate, there are 16 moles of oxygen atoms (from the two oxygen atoms in each formula unit). The molar mass of oxygen is 16 g/mol, so in 2 moles of potassium dichromate, there are 32 grams of oxygen.


How many nitrogen atoms are in 18.8 g of barium nitride?

Barium nitride is Ba3N2 (from the rules of ionic bonding). Its molar mass is 439 grams/mole (from the periodic table), so 18.8 grams of it is 0.0428 moles (by algebraic direct proportion). Multiply this by Avogadro's number (6.02x1023; the number of particles in 1 mole) and you get 2.58x1022 formula units of barium nitride, and there are 2 nitrogen atoms per formula unit, so double it to 5.16x1022 atoms of nitrogen.


How many oxygen atoms are present in 3 moles of potassium nitrate?

3KNO3, so 9 oxygen atoms.


How many atoms are in 0.3 moles of potassium?

0.3 moles K (6.022 X 10^23/1mol K) = 1.8 X 10^23 atoms of K