1 g x ( 1 mole / 58.7 g ) x ( 6.022 x 1023 atoms / mole) = 1.03 x 1022 atoms
58.69 g (or 1 mole) of nickel has 6.023 x 1023 atoms.
If you mean nickel the metal, then it depends on how big a piece.
If you mean a nickel the US coin ... about 4.8 x 10^22.
6.02 x 10^23
Nickel has just one atom
1...
7.378 atoms
28 protons
30 neutrons
71.9
Ni(OH)2 1 atom of nickel 2 atoms of oxygen 2 atoms of hydrogen -------------------------------+ total atoms = 5 atoms
A nickel weighs 5 grams. It is 75% nickel and 25% copper. The atomic weight of nickel is 58.71 and the atomic weight of copper is 63.54. So there is 0.0639 moles of nickel and 0.0197 moles of copper in a US nickel. There are 6.02 * 10^23 atoms in a mole (Avogadro's number). There are 6.02 * 10^23 * 0.0639 = 3.48 * 10^22 atoms of nickel, and 6.02 * 10^23 * 0.0197 = 1.184 * 10^22 atoms of copper. Since a nickel atom contains 28 electrons, and a copper atom contains 29 electrons, we have 9.744 * 10^23 electrons for the nickel component, and 3.433 * 10^23 electrons for the copper component. Total is 1.317 * 10^24 electrons.
There are 58.6934 gram in one mole of Ni atoms, so there are125(g Ni) / 58.6934 (g.mol-1 Ni) = 2.13 moles in 125 gram Ni
The compound name for NiCl2 is Nickel Chloride. It is comprised of one atom of Ni, Nickel, and two atoms of Chlorine which becomes a Chloride.
Nickel has 28 protons; thus, it has 28 electrons.
Ni(OH)2 1 atom of nickel 2 atoms of oxygen 2 atoms of hydrogen -------------------------------+ total atoms = 5 atoms
Nickel Hydroxide is Ni(OH)2. So 1 molecule of Nickel Hydroxide contains 2 oxygen atoms.
2 i think
Nickel's atomic number is 28, which means that all nickel atoms contain 28 protons in their nuclei.
Nickel is 58.7g/mol, so 26.4/58.7=0.45mol, and that times 6.02x1023 (Avogadro's number) gives you 2.71x1023 atoms of nickel.
First you have to find out the number of moles of Nickel in 0.63g. Do this by dividing 0.63 by the molecular weight of Nickel; 58.69g. 0.63/58.69= 0.01 mol (2 d.p.) In one mole there are 6.02x1023 atoms. Therefore in 0.01 moles of Nickel there will be: 0.01 x 6.02x1023 = 9.15x1015 atoms.
He
Avogadro's number times 5.6 (or about 33.6 times ten to the 23rd power.
same no of protons
A sample of 3,2x10 atoms of nickel is equal to 0,53.10e-23 moles.
A nickel weighs 5 grams. It is 75% nickel and 25% copper. The atomic weight of nickel is 58.71 and the atomic weight of copper is 63.54. So there is 0.0639 moles of nickel and 0.0197 moles of copper in a US nickel. There are 6.02 * 10^23 atoms in a mole (Avogadro's number). There are 6.02 * 10^23 * 0.0639 = 3.48 * 10^22 atoms of nickel, and 6.02 * 10^23 * 0.0197 = 1.184 * 10^22 atoms of copper. Since a nickel atom contains 28 electrons, and a copper atom contains 29 electrons, we have 9.744 * 10^23 electrons for the nickel component, and 3.433 * 10^23 electrons for the copper component. Total is 1.317 * 10^24 electrons.
The compound name for NiCl2 is Nickel Chloride. It is comprised of one atom of Ni, Nickel, and two atoms of Chlorine which becomes a Chloride.