First you have to find out the number of moles of Nickel in 0.63g. Do this by dividing 0.63 by the molecular weight of Nickel; 58.69g.
0.63/58.69= 0.01 mol (2 d.p.)
In one mole there are 6.02x1023 atoms. Therefore in 0.01 moles of Nickel there will be:
0.01 x 6.02x1023 = 9.15x1015 atoms.
3,09x10e24 atoms of sulfur in grams is equal to 164,65 g.
23 g (6.02 x 1023 at / 4.00 g) = 3.5 x 1024atoms
To find the number of atoms in 175 grams of calcium, you first need to calculate the number of moles of calcium using its atomic weight. Then, use Avogadro's number (6.022 x 10^23 atoms per mole) to convert moles to atoms.
how many grams is 39cc?
To calculate the number of atoms, we need to use Avogadro's number and the molecular weight of zinc. The molar mass of zinc is 65.38 g/mol. First, convert grams to moles: 135 g / 65.38 g/mol = 2.06 moles. Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms: 2.06 moles * 6.022 x 10^23 atoms/mol = 1.24 x 10^24 atoms of zinc.
3,09x10e24 atoms of sulfur in grams is equal to 164,65 g.
28.5 g (6.02 x 1023 at / 12.01 g) = 1.43 x 1024atoms
To calculate the grams in 7.97 x 10^24 atoms of calcium, you need to divide the number of atoms by Avogadro's number (6.022 x 10^23). Then multiply this result by the molar mass of calcium (40.08 g/mol). This calculation would give you the weight in grams of 7.97 x 10^24 atoms of calcium.
So, there are approximately 8.74 × 1 0 24 8.74×10 24 hydrogen atoms in 800 grams of C 3 H 8 C 3 H 8 .
2.408 x 10^24 atoms.
2 mol 1.204*10^24=2*6.02*10^23 so the amount is 2 mols
A nickel weighs 5 grams. It is 75% nickel and 25% copper. The atomic weight of nickel is 58.71 and the atomic weight of copper is 63.54. So there is 0.0639 moles of nickel and 0.0197 moles of copper in a US nickel. There are 6.02 * 10^23 atoms in a mole (Avogadro's number). There are 6.02 * 10^23 * 0.0639 = 3.48 * 10^22 atoms of nickel, and 6.02 * 10^23 * 0.0197 = 1.184 * 10^22 atoms of copper. Since a nickel atom contains 28 electrons, and a copper atom contains 29 electrons, we have 9.744 * 10^23 electrons for the nickel component, and 3.433 * 10^23 electrons for the copper component. Total is 1.317 * 10^24 electrons.
To find the weight of 4.2x10^24 atoms of oxygen, you need to know the atomic mass of oxygen. The molar mass of oxygen is about 16 grams per mole. So, you can calculate the weight by dividing the number of atoms by Avogadro's number to get the number of moles, and then multiply by the molar mass. In this case, it would be: (4.2x10^24 atoms) / (6.022x10^23 atoms/mol) * 16 grams/mol = approximately 112 grams.
82.5 grams O2 (1 mole O2/32 grams)(6.022 X 10^23/1 mole O2) = 1.55 X 10^24 atoms of O2
There are 10,886.2169 grams in 24 pounds.
23 g (6.02 x 1023 at / 4.00 g) = 3.5 x 1024atoms
To calculate the mass of 1.14x10^24 atoms of iodine, you would first determine the molar mass of iodine (I), which is approximately 126.9 g/mol. Then, you would use Avogadro's number (6.022x10^23 atoms/mol) to find the mass. Therefore, the mass of 1.14x10^24 atoms of iodine would be approximately (1.14x10^24 atoms / 6.022x10^23 atoms/mol) * 126.9 g/mol = 241 grams.