28.5 g (6.02 x 1023 at / 12.01 g) = 1.43 x 1024atoms
24 grams carbon (1 mole C/12.01 grams)(6.022 X 10^23/1 mole C)
= 1.2 X 10^24 atoms of carbon
24 grams is the equivalent of two moles of carbon-12.
80. g Argon
72.0 grams Carbon (1 mole C/12.01 grams)(6.022 X 10^23/1 mole C) = 3.61 X 10^24 atoms of carbon
77.28 grams C2H6 (1 mole C2H6/30.068 grams)(2 mole C/1 mole C2H6)(6.022 X 10^23/1 mole C) = 3.096 X 10^24 atoms of carbon
There are 24 moles of Carbon (C) in 2 moles of table sugar (sucrose)
52.06 grams carbon dioxide (1 mole CO2/44.01 grams)(2 mole O/1 mole CO2)(6.022 X 10^23/1 mole O) = 1.425 X 10^24 atoms of oxygen --------------------------------------------
When calculating calcium you must first see how many moles are there. There are 2.6Ã?10^24 atoms in 173 grams of calcium.
72.0 grams Carbon (1 mole C/12.01 grams)(6.022 X 10^23/1 mole C) = 3.61 X 10^24 atoms of carbon
2.936*10^24 atoms....
77.28 grams C2H6 (1 mole C2H6/30.068 grams)(2 mole C/1 mole C2H6)(6.022 X 10^23/1 mole C) = 3.096 X 10^24 atoms of carbon
18 carbon atoms
There are 24 moles of Carbon (C) in 2 moles of table sugar (sucrose)
# of moles = Mass÷ Formula weight Example: 6 grams of Carbon atoms Carbon has an atomic mass of 12 grams so according to the Equation # of moles = 6÷ 12 = 0.5 moles For a compound such as CO2 , Formula weight = ( 1 mole of carbon atom weighs 12 grams + 2 moles of oxygen atoms weighs 32 grams ) 44 grams. Example: 24 grams of carbon dioxide = 24÷ 44 = 0.5454 moles So for sodium, # of moles = 45.48 g ÷ 22.99g/mole = moles You divide!
52.06 grams carbon dioxide (1 mole CO2/44.01 grams)(2 mole O/1 mole CO2)(6.022 X 10^23/1 mole O) = 1.425 X 10^24 atoms of oxygen --------------------------------------------
The questions asks how many moles of carbon atoms.Molar mass is defined as the mass of one mole of a substance or in this case 6.022x1023 atoms of carbon. So the molar mass for carbon is 12.0 g/mol. Therefore the number of moles of carbon atoms is just 36/12.0 = 3.0 moles of carbon.How many atoms are in 36 grams of Carbon?[36 (gC) /12.0 (gC/molC)] * 6.02*10+23 (atoms C/molC) = 1.8*10+24 atoms in 36 g Carbon
3,09x10e24 atoms of sulfur in grams is equal to 164,65 g.
I think you meant 3.09x10^24 atoms of sulfur. 3.09x10^24 atoms * (1 mol / 6.02x10^32 atoms) * (32 g / 1mol) = 165 grams
7.97 X 10^24 atoms Ca (1 mole Ca/6.022 X 10^23)(40.08 grams/1 mole Ca) = 530 grams of calcium
If the density of carbon tetrachloride is 1.59 g/L, the volume in L of 4.21 kg of carbon tetrachloride is about 2,647.8 L