To find the number of atoms we need to find number of moles of Fe in 312.0 grams.
Molar weight of Fe = 56
Number of moles of Fe in 312 grams = 312/56
=5.571 moles.
1 mole of Fe has Avogadro number of atoms.
So 5.571 moles of Fe has atoms = 5.571 * Avogadro number.
Avogadro number = 6.022 * 10^23
So total atoms = 5.571 * 6.022 * 10^23
= 33.548 * 10^23
* means multiply, ^ means raised to power.
300g * 6.02*1023moles of Fe /56 g Fe= 3.2*1024 atoms
600 grams of iron contain 64,70.10e23 atoms.
That depends. For the most common form of Iron (Iron-56), there are 56 grams. You may also call 6.02 X 10^23 atoms/molecules a "mole" of atoms/molecules.
25,1 grams sulfur contain 4,7147765.10e23 atoms.
The answer is 9,17233.1023 atoms.
divide the number of atoms by avogadros number (6.022*10^23), the resulting number is the number of moles you have. Multiply the number of moles of atoms by the molar mass (found on any periodic table) and the answer is how many grams of the substance you have.
If iron(II), then iron sulfate is FeSO4. This has a single Fe atom per molecule (or two Fe in two molecules). If you have iron(III), then iron sulfate is Fe2(SO4)3. This compound has two iron atoms per molecule (or four Fe in two molecules).
738 grams iron are equivalent to:- 12,626 moles- 76.10e23 atoms
6.355 x 10e10 atoms of iron contain 58,93.e-13 grams
That depends. For the most common form of Iron (Iron-56), there are 56 grams. You may also call 6.02 X 10^23 atoms/molecules a "mole" of atoms/molecules.
Five iron atoms have a mass of 1.3155 x 10-22 grams.
Rusted iron is FeO, iron oxide. 63.8 grams FeO (1 mole FeO/71.85 grams)(6.022 X 1023/1 mole FeO) = 5.35 X 1023 atoms of iron oxide -------------------------------------------
If you suppose that the nail is pure iron, this material has atoms not molecules.And the number of atoms in 3 g is 0,32535.10e23.
Impossible to answer without knowing a mass or a volume. But I can tell you that there are 6.022x10^23 iron atoms (one mole) for every 55.845 grams of iron. That translates to: 1.078x10^22 iron atoms per gram or given that the density of iron is 7.87 g/cm3 at 25 degrees Celsius... 8.487x10^22 iron atoms per cm3.
The formula of iron (III) sulfide is Fe2S3, showing that each formula unit contains two iron atoms. The gram formula unit mass for iron (III) sulfide is 207.87, and the gram atomic mass of iron is 55.847. Therefore, the fraction by mass of iron in iron (III) sulfide is 2(55.847)/207.87 or about 0.5373, and the grams of iron in 130 g of iron (III) sulfide is 0.5373 X 130 or 69.9 grams, to the justified number of significant digits.
10 milligrams iron (1 gram/1000 milligrams)(1 mole Fe/55.85 grams)(6.022 X 1023/1 mole Fe) = 1.1 X 1020 atoms of iron ===================
The answer is 38,174.10ex.23 atoms
The number of atoms in a given mass of metal may be calculated by dividing the mass by the gram atomic mass, then multiplying by Avogadro's Number. The gram atomic masses of iron and copper are 55.847 and 63.546 respectively. Since Avogadro's Number is constant, the required mass m of copper atoms can be found from the equation m/63.546 = 235/63.546, or m = 235 X (63.456/55.847), or 267 grams of copper, to the justified number of significant digits.
169 milligrams iron (1 gram/1000 milligrams)(1 mole Fe/55.85 grams)(6.022 X 10^23/1 mole Fe) = 1.82 X 10^21 atoms of iron --------------------------------------