Rusted iron is FeO, iron oxide.
63.8 grams FeO (1 mole FeO/71.85 grams)(6.022 X 1023/1 mole FeO)
= 5.35 X 1023 atoms of iron oxide
-------------------------------------------
6.355 x 10e10 atoms of iron contain 58,93.e-13 grams
Five iron atoms have a mass of 1.3155 x 10-22 grams.
Iron oxide (rust) Isn't magnetic. So rusted iron will have less pure iron in it. making it less magnetic.
Impossible to answer without knowing a mass or a volume. But I can tell you that there are 6.022x10^23 iron atoms (one mole) for every 55.845 grams of iron. That translates to: 1.078x10^22 iron atoms per gram or given that the density of iron is 7.87 g/cm3 at 25 degrees Celsius... 8.487x10^22 iron atoms per cm3.
10 milligrams iron (1 gram/1000 milligrams)(1 mole Fe/55.85 grams)(6.022 X 1023/1 mole Fe) = 1.1 X 1020 atoms of iron ===================
oxygen atoms are added to iron atoms to form a molcule with a combined mass of iron and oxygen
738 grams iron are equivalent to:- 12,626 moles- 76.10e23 atoms
Left intact the rusted bolt because it has the added mass of the Oxygen. Once cleaned up it will be lighter because it has lost mass in the form of iron atoms in the Iron Oxide molecules.
6.355 x 10e10 atoms of iron contain 58,93.e-13 grams
That depends. For the most common form of Iron (Iron-56), there are 56 grams. You may also call 6.02 X 10^23 atoms/molecules a "mole" of atoms/molecules.
Rusted iron is not pure iron; it is an iron oxide.
Five iron atoms have a mass of 1.3155 x 10-22 grams.
Iron oxide (rust) Isn't magnetic. So rusted iron will have less pure iron in it. making it less magnetic.
Rusted cast iron.
Avogadros number (approximately). The atomic weight of iron is 55.845. Avogadros number , the number of atoms in a mole of an element, or the number of molecules in a mole of a compound is 6.023 X 1023
First you need to find the atomic weights of all the elements involved and add them up (including how many atoms of the same element there are) to find the total molecular mass.Fe = 55.9 grams × 2 atoms = 111.8 gramsO = 16 grams × 3 atoms = 48 grams________________________________________Fe2O3 = 159.8 gramsThen you take the weight of iron in one mole of the compound and divide it by the total weight to get its percent composition.111.8 grams Fe ÷ 159.8 Fe2O3 grams = .6996 = 69.96% Fe in Fe2O3Then we apply this percentage to 639 kg. The thought process is as follows: if there is 69.96% of iron in Fe2O3 by weight, then 69.96% of 639 kg of the substance is iron.69.96% of 639 kg = .6996 × 639 = 447.1 kilograms of Fe in 639 kilograms of Fe2O3
Rust on iron is a hydrated iron oxide.