1 mole Al = 6.022 x 1023 atoms Al
0.2mol Al x 6.022 x 1023 atoms Al/1mol Al = 1 x 1023 atoms Al (rounded to 1 significant figure)
27g
Depending on the thickness of the foil.
The electron configuration for aluminum atoms, which is 1s22s22p63s23p1.
The scientist that suggested and proved that atoms contained a nucleus in which most of the weight of the atom was contained (in a very small volume) was Ernest Rutherford, in 1909. This was shown in the 'gold foil' experiment. This was made by shooting positively charged alpha particles, or a positively charged helium atom (2 protons, 2 nuetrons). these then when shot at the gold foil. some of the alpha particles just passed through the gold foil, but some were deflected. this proving that some hit the nucleus while others did not.
that the atom mostly consisted of empty space.
contain a positively charged, dense center
27g
Depending on the thickness of the foil.
aluminum
atoms
most of the alpha particle pass through the gold foil without deviation and the mass of electron are very small
In Rutherford's gold foil experiment atoms are mostly empty space.
Blister Packing contain PVC foil (0.25mm) and Alu. foil (0.025mm) Strip Packing contain Bothside Poly alu. foil (0.30mm)
Ernest Rutherford, following the "gold foil" experiment.
Anybody who knows much about atoms and is willing to ignore virtual particles. The credit for actually discovering this should probably go to Rutherford. (Or Rutherford, Geiger, and Marsden ... Geiger and Marsden actually did the experiment in Rutherford's lab, and Rutherford was the one who explained the results.)
Rutherford, with his gold foil experiment.
The electron configuration for aluminum atoms, which is 1s22s22p63s23p1.