To find the number of atoms in 0.575 grams of cesium, you first need to convert grams to moles using the molar mass of cesium. Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms in one mole of cesium. Multiply the number of moles by Avogadro's number to find the number of atoms in 0.575 grams of cesium.
3,45 grams of H2O contain 1,154.10e23 oxygen atoms.
There are approximately 3.633 x 10^23 carbon atoms in 21.84 grams of carbon.
There are approximately 1.93 x 10^23 atoms in 300 grams of gold. This is calculated using Avogadro's number (6.022 x 10^23 atoms/mole) and the molar mass of gold (197 grams/mole).
The molar mass of sulfur is approximately 32 grams per mole. Therefore, 100 grams of sulfur would contain approximately 3 moles of sulfur atoms (100 grams / 32 grams/mole). To find the number of atoms, you would then multiply the number of moles by Avogadro's number (6.022 x 10^23 atoms/mole) to get the total number of sulfur atoms in 100 grams.
Two elements...Three Caesium atoms and two Nitrogen atoms
1,25 grams of CH4 contain 0,156696.10e23 atoms.
738 grams iron are equivalent to:- 12,626 moles- 76.10e23 atoms
3,45 grams of H2O contain 1,154.10e23 oxygen atoms.
45,0 grams of hydrogen gas have 135,5.10e23 atoms.
3.05 x 1025
There are approximately 3.633 x 10^23 carbon atoms in 21.84 grams of carbon.
The answer is 47,128 x 1023 atoms.
There are 57.6 grams of tin in that sample.
6.355 x 10e10 atoms of iron contain 58,93.e-13 grams
The answer is 13,367.1010e+23 atoms.
55.8 grams
How many neutrons are in Cesium-130 (Cs)?