I assume you mean 4.6 X 10^25 atoms. This is the conversion. 4.6 X 10^25 atoms Cu ( 1mol Cu/ 6.022 X 10^23 )( 63.55 grams Cu/ 1 mol Cu ) = 4854.37 grams Cu
Divide that number of atoms by 6.02x10^23 atoms/mole
4.0 moles Cu (6.022 X 1023/1 mole Cu) = 2.4 X 1024 atoms of copper ====================
Copper nitrate molecule contain nine atoms.
There is no CuSO. If you mean CuSO4, it would be 6 atoms per formula unit; one Cu atom, one S atom, and 4 O atoms.
1.2 g Cu * (1 mole Cu / 63.54 g Cu)*(6.022x1023 atoms Cu / mole Cu)1.137x1022 atoms of copper
Cu(NO3)2 has 9 atoms 1 Cu atom 2 N atoms 6 O atoms
Answer: 1.14x10^23 atoms Cu (12.0g Cu/63.55amu(g) Cu) Then take (Ans x 6.022x10^23) = 1.13712038x10^23 atoms Cu. Then I simplified it to 3 sig figs. = 1.14x10^23 atoms Cu Never forget your units and substance!
I assume you mean 4.6 X 10^25 atoms. This is the conversion. 4.6 X 10^25 atoms Cu ( 1mol Cu/ 6.022 X 10^23 )( 63.55 grams Cu/ 1 mol Cu ) = 4854.37 grams Cu
Divide that number of atoms by 6.02x10^23 atoms/mole
4.0 moles Cu (6.022 X 1023/1 mole Cu) = 2.4 X 1024 atoms of copper ====================
1 mol Cu Atoms (6.02x10^23 atoms)
1 w
Copper nitrate molecule contain nine atoms.
There is no CuSO. If you mean CuSO4, it would be 6 atoms per formula unit; one Cu atom, one S atom, and 4 O atoms.
The products will contain 4 Cu atoms, 5 O atoms, and 10 H atoms.
Copper nitrate has six atoms of oxygen.