Okay, 1 mole of any substance contains 6.02x1023 representative particles. So, if you have a mole of C2H6 (ethane), you have Avogadro's number of molecules. You're asking about atoms, so if you look at the formula for ethane, you see 2 carbons and 6 hydrogens for a total of 8 atoms per molecule. Multiply Avogadro by 8 to get the total number of atoms. Then multiply by the given number of moles.
6.02x1023 x 8 (#of atoms) x 5.6 (number of moles) = 269.7x1023 = approximately 2.7x1025 atoms.
To determine the number of atoms in 560 cm3 of ammonia at STP (Standard Temperature and Pressure), we first need to calculate the number of moles of ammonia present. The molar volume of a gas at STP is 22.4 L/mol, which is equivalent to 22,400 cm3/mol. Therefore, 560 cm3 is equal to 0.025 moles of ammonia. Next, we use Avogadro's number, 6.022 x 10^23 atoms/mol, to find that there are approximately 1.51 x 10^22 ammonia molecules in 560 cm3 at STP.
Using the ideal gas law, at STP (standard temperature and pressure), 1 mole of gas occupies 22.4 liters. Therefore, a balloon with 560 liters at STP would contain 25 moles of gas (560 liters / 22.4 liters/mole).
560 grams is exactly .560 Kilograms.
560 / 8 = 70
It is: 560/7 = 80
There are 70 8s in 560
This enthalpy of reaction is 560 joules, for liquid water at 25 oC.
560 kilograms = 1,234.5 pounds.
560 minutes = 9.33333333 hours
560 kilometers = 1,837,270.34 feet
5.6 meters = 560 centimeters
560 crore = 5600 million