0.250 mol
Molarity = moles of solute/Liters of solutionOr, for our purposes....,Liters of solution (volume) = moles of solute/MolarityVolume (liters) = 0.150 moles HCl/4.00 M HCl= 0.0375 liters = 37.5 milliliters======================
The molarity is 0,025.
To calculate the amount of helium in the balloon, we need to convert the mass of helium gas to moles using the molar mass of helium. The molar mass of helium is 4 g/mol. So, 0.54 grams of helium is equal to 0.54/4 = 0.135 moles of helium. Finally, we can use Avogadro's principle to convert moles to the number of helium atoms present in the balloon.
This molarity is 1,59.
first you need to know the number of liters and moles and the equation. you do someting then multiply the liters times the moles. first you need to know the number of liters and moles and the equation. you do someting then multiply the liters times the moles.
At STP (standard temperature and pressure), 1 mole of any gas occupies 22.4 liters. In this case, the balloon contains 3.6 L of CH4, so the number of moles of gas present can be calculated by dividing 3.6 by 22.4. This would result in approximately 0.161 moles of gas.
Molarity = moles of solute/Liters of solutionOr, for our purposes....,Liters of solution (volume) = moles of solute/MolarityVolume (liters) = 0.150 moles HCl/4.00 M HCl= 0.0375 liters = 37.5 milliliters======================
Molarity is moles of solvent divided by liters of solution, so 6.42 / 1.75 = 3.67M.
The molarity is 0,025.
To calculate the amount of helium in the balloon, we need to convert the mass of helium gas to moles using the molar mass of helium. The molar mass of helium is 4 g/mol. So, 0.54 grams of helium is equal to 0.54/4 = 0.135 moles of helium. Finally, we can use Avogadro's principle to convert moles to the number of helium atoms present in the balloon.
This molarity is 1,59.
Molar means moles per litre. Therefore, you need to divide 1.4 by 3.2 to get an answer per litre. 1.4/3.2 is 0.4375 molar.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution in liters. In this case, the molarity would be 0.15 M, which is calculated by dividing 0.45 moles by 3.0 liters.
To estimate the size of a balloon filled with 17.8 grams of air, we can use the ideal gas law. At standard temperature and pressure (STP), 1 mole of gas occupies about 22.4 liters. Given that the molar mass of air is approximately 29 g/mol, 17.8 grams of air corresponds to about 0.61 moles, which would occupy roughly 13.7 liters. Therefore, the balloon would have a volume of approximately 13.7 liters when filled with 17.8 grams of air.
To find the number of oxygen molecules in the balloon, you can first calculate the number of moles of O2 using its molar mass (32 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. In this case, the balloon contains approximately 1.15 x 10^23 oxygen molecules.
Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============
first you need to know the number of liters and moles and the equation. you do someting then multiply the liters times the moles. first you need to know the number of liters and moles and the equation. you do someting then multiply the liters times the moles.