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Q: What is the molarity of a solution that contains 0.202 moles KCl in 7.98 liters of solution?

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2.5m

Molarity = moles of solute/Liters of solution ( 500.0 ml = 0.5 Liters ) Molarity = 0.75 moles/0.5 Liters = 1.5 M

Molarity is moles divided by volume in Litres.So 8.5/2.3 = 3.7 mole/L = 3.7 M

Molarity = moles of solute/volume of solution M = 0.25 moles/0.50L = 0.5M

The molarity is 0.718 moles/litre.

Related questions

Molarity = moles of solute/liters of solution Molarity = 7 moles solute/2 Liters solution = 3.5 M ======

I believe the molarity is 1. molarity = number of moles / liters of solution molarity = 3 / 3 = 1

This molarity is 1,59.

Molarity = moles of solute/Liters of solution Molarity = 0.202 moles KCl/7.98 Liters = 0.253 M KCl solution ================

Molarity is moles of solvent divided by liters of solution, so 6.42 / 1.75 = 3.67M.

3m

bv

2.5m

3 moles per liter.

Molarity = moles of solute/liters of solution Molarity = 5 moles sucrose/0.5 Liters = 10 M sucrose solution =================

Molarity = moles of solute/Liters of solution Molarity = 6 moles AgClO4/2 Liters = 3 M AgClO4 =========

molarity = moles/litre [solution] = 6 mol/2 L [solution] = 3 M

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