Chemistry
Volume
Acids and Bases

If 25 moles of sucrose are mixed into 50 liters of water what is the molarity?

234

Top Answer
User Avatar
Wiki User
Answered
2011-03-21 20:38:11
2011-03-21 20:38:11

Molarity = moles of solute/Liters of solution

Molarity = 25 moles sucrose/50 liters H2O

= 0.5 M sucrose

001
๐ŸŽƒ
0
๐Ÿคจ
0
๐Ÿ˜ฎ
0
๐Ÿ˜‚
0
User Avatar

Related Questions


Molarity = moles of solute/liters of solution Molarity = 5 moles sucrose/0.5 Liters = 10 M sucrose solution =================


Molarity is defined as moles solute/liter of solution.Moles of solute = 2.5 moles sucrose Liters of solution = 0.5 liters Molarity (M) = 2.5 moles/0.5 liters = 5 M


Molarity = moles of solute/Liters of solution Molarity = 5 moles sucrose/0.5 Liters = 10 M ----------


Molarity = moles of solute/Liters of solution Molarity = 2.5 moles NaOH/10 Liters = 0.25 M NaOH ==========


Molarity = moles of solute/Liters of solution Molarity = 6 moles AgClO4/2 Liters = 3 M AgClO4 =========


Molarity = moles of solute/liters of solution Molarity = 0.597 moles HCl/0.169 liters = 3.53 M HCl ------------------


Molarity = moles of solute/Liters of solution ( 500.0 ml = 0.5 Liters ) Molarity = 0.75 moles/0.5 Liters = 1.5 M


Molarity = moles of solute/Liters of solution Molarity = 10 moles salt/20 Liters solution = 0.50 M salt solution ----------------------------


Molarity = moles of solute/Liters of solution ( 500.0 ml =0.500 Liters ) Molarity = 0.75 moles/0.500 Liters = 1.5 M ----------


MOLARITY = number of moles/ volume in liters so if you have the volume along with the molarity you can calculate


Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========


Molarity = moles of solute/liters of solution Molarity = 7 moles solute/2 Liters solution = 3.5 M ======


1620 ml = 1.62 Liters Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/1.62 Liters = 1 M NaOH solution ===============


M (molarity) = moles of solute/ liters of solution


Molarity = moles solute/ Liters solution


Molarity (M) represents the moles of a solute per liter of a solvent. In this case, sucrose is the solute and water is the solvent. First, convert your 125g of sucrose to moles...molar mass of sucrose = 342.34 soo you have .365 moles of sucrose. Since you have exactly one L of solution, the molarity of the solution is .365 M Molarity (M) represents the moles of a solute per liter of a solvent. In this case, sucrose is the solute and water is the solvent. First, convert your 125g of sucrose to moles...molar mass of sucrose = 342.34 soo you have .365 moles of sucrose. Since you have exactly one L of solution, the molarity of the solution is .365 M


Molarity = moles of solute/Liters of solution so, 959 milliliters = 0.959 Liters Molarity = 7.0 moles of solute/0.959 Liters = 7.3 M solute ===========


Molarity = moles of solute/Liters of solution ( 230 ml = 0.0230 Liters) Molarity = 2.60 moles LiCl/0.230 Liters = 11. 3 M LiCl -----------------


Molarity = moles of solute/Liters of solution ( 5000 ml = 5 Liters ) Molarity = 90 moles solute/5 Liters = 18 M --------------------the most concentrated possible


since molarity = (number of moles) / (volume of solution), the molarity of a solution with 2.3 moles of sodium chloride in 0.45 liters of water will be 5.11 moles.


Molarity = moles of solute/Liters of solution Or, for our purposes, Moles of solute = Liters of solution * Molarity Moles Na2CO3 = 10.0 Liters * 2.0 M = 20 moles Na2CO3 --------------------------


Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============


Molarity = moles of solute/Liters of solution Molarity = 5 moles solute/4.5 Liters of solution = 1 M solution ==========


Molarity = moles of solute/Liters of solution ( 1500 mL = 1.5 Liters ) Molarity = 0.800 moles NaOH/1.5 Liters = 0.533 M sodium hydroxide ==================


Molarity = moles of solute/Liters of solution (40 ml = 0.04 Liters) algebraically manipulated, Moles of solute = Liters of solution * Molarity Moles HCl = (0.04 Liters)(0.035 M) = 0.0014 moles HCl ==============



Copyright ยฉ 2020 Multiply Media, LLC. All Rights Reserved. The material on this site can not be reproduced, distributed, transmitted, cached or otherwise used, except with prior written permission of Multiply.