6.02*10^26
7.66 X 10^5 millimols argon (1 mole argon/1000 mmol)(6.022 X 10^23/1 mole Ar) = 4.61 X 10^25 atoms of argon
The number is Avogadro's number, 6.0221409 *10^23
A mole of argon includes Avogadro's Number of atoms of argon. Therefore, the answer is (3.0 X 1024)/(6.022 X 1023) or 5.0 moles, to the justified number of significant digits.
Using eight significant figures, there are 6.0221421 X 10^23 carbon atoms present in a mole of 12c.
6.02214076×1023
7.66 X 10^5 millimols argon (1 mole argon/1000 mmol)(6.022 X 10^23/1 mole Ar) = 4.61 X 10^25 atoms of argon
The number is Avogadro's number, 6.0221409 *10^23
A mole of argon includes Avogadro's Number of atoms of argon. Therefore, the answer is (3.0 X 1024)/(6.022 X 1023) or 5.0 moles, to the justified number of significant digits.
just divide the mass of sample by the mass of argon. OR: atomic mass of argon is 40 g/mol, so in a 40g sample of argon, there ought to be 1 mole atoms, or 6.02x10^23 atoms
4,80 moles of Fe contain 28,9062761136.10e23 atoms.
6.023 x 1023
Using eight significant figures, there are 6.0221421 X 10^23 carbon atoms present in a mole of 12c.
2
6.02214076×1023
0.375 mole Pd (6.022 X 10^23/1 mole Pd) = 2.26 X 10^23 atoms of Pd
No, hydrogen is a diatomic atom, which means it bonds with itself naturally, and since argon it is a noble gas, it is found alone in nature. This means that 1 molecule of hydrogen has two atoms, while 1 molecule of Argon has 1 atom.
There are 6.022 × 1023 atoms of potassium in every mole of potassium. Since one mole of KOH contains one mole of K, the answer is 6.022×1023 atoms of K. Therefore, 3.5 moles * 6.022E23 atoms/1 mole= 2.107E24