Atomic Mass of Ag: 107.9 grams
5.00 grams × (6.02 × 1023 atoms) / (107.9 grams) = 2.79 × 1022 atoms Ag
If 3,6 x 10-5 is grams the number of atoms is 1,1.10e17.
5 grams of gold is in 5 grams of gold dust
well... it depends on how many karats the gold is... -_-
5x10-3 g divided by m.wt. of gold (197 g/mol) equals 2.5x10-5 mol gold.2.5x10-5 mol gold multiplied by Avogadro's Number (6.023x10+23 atoms/mol) equals 1.5x10+20 atoms.
For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023. AuCl3= 303.5 grams5.00 grams AuCl3 / (303.5 grams) × (6.02 × 1023 atoms) = 9.92 × 1021 atoms
5.0 grams gold (1 mole Au/197.0 grams)(6.022 X 1023/1 mole Au) = 1.5 X 1022 atoms of gold ===================
If 3,6 x 10-5 is grams the number of atoms is 1,1.10e17.
5 grams of gold is in 5 grams of gold dust
well... it depends on how many karats the gold is... -_-
5
1 Ounce = 28.3495231 Grams
141.74 g
The gram atomic mass of gold is 196.967 and that of potassium is 39.0983. Therefore, equal numbers of atoms of potassium are supplied by 39.0983/196.967 the mass of potassium compared with gold. 5 X 9.85 = 49.25. This contains the same number of gold atoms as 49.25(39.0983/196.967) or 9.78 grams of potassium contains of potassium atoms, to the justified number of significant digits (limited by the number "9.85", assuming that "5" is intended to be exact.)
3.121x10-5 Grams of Na2CO3
6.6x1022 per gram of water
5x10-3 g divided by m.wt. of gold (197 g/mol) equals 2.5x10-5 mol gold.2.5x10-5 mol gold multiplied by Avogadro's Number (6.023x10+23 atoms/mol) equals 1.5x10+20 atoms.
5 liters