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For this problem, the Atomic Mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023. AuCl3= 303.5 grams

5.00 grams AuCl3 / (303.5 grams) × (6.02 × 1023 atoms) = 9.92 × 1021 atoms

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How many grams of AuCl3 can be made from 100.0 grams of chlorine by this reaction Au plus Cl3 AuCl3?

The molar mass of chlorine is 35.45 g/mol. From the equation, 3 moles of chlorine are needed to form 1 mole of AuCl3. Therefore, 100.0 grams of chlorine corresponds to 100.0 g / 35.45 g/mol = 2.82 moles of Cl2. This would allow the formation of 2.82 / 3 = 0.94 moles of AuCl3. Finally, the molar mass of AuCl3 is 303.33 g/mol, which means 0.94 moles of AuCl3 would be equivalent to 0.94 mol * 303.33 g/mol = 285.53 grams of AuCl3.


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