The answer is 12, 044 280.1023 atoms.
To find the number of moles of potassium, we need to first determine the molar quantity of potassium atoms in one mole. A mole is equivalent to Avogadro's number, which is 6.022e23 atoms per mole. So, 7.85e23 potassium atoms would be approximately 1.304 moles of potassium.
3KNO3, so 9 oxygen atoms.
10.0 moles K2SO4 (6.022 X 1023/1 mole K2SO4) = 6.02 X 1024 atoms of potassium sulfate ==========================
6.02*10^23 atoms in 1 mole of any element! (The fact that it is potassium is not important.) 6.02*10^23 atoms * 2.5 = 1.5 × 1024 (remember that there are two significant digits)
0.0384 moles K x 6.02x10^23 atoms/mole = 2.31x10^22 atoms
The number of atoms is 101,341.10e23.
Since molecules of potassium contain only single potassium atoms, molecules of iodine contain two atoms, and moles of potassium iodide contain one atom of each element, 2.5 moles of iodine are needed to react completely with 5 moles of potassium.
To find the number of moles of potassium, we need to first determine the molar quantity of potassium atoms in one mole. A mole is equivalent to Avogadro's number, which is 6.022e23 atoms per mole. So, 7.85e23 potassium atoms would be approximately 1.304 moles of potassium.
Four (4) mol of potassium are represented.
To find the number of potassium atoms in a sample of K2Cr2O7, you first need to calculate the number of moles of K2Cr2O7 using its molar mass. Then, you can determine the number of moles of potassium atoms since there are 2 potassium atoms in each molecule of K2Cr2O7. Finally, use Avogadro's number (6.022 x 10^23) to convert the number of moles of potassium atoms to the actual number of atoms.
Two times Avogadro's number (6.022×10 to the 23)
To find the number of moles, you first need to recognize that 6.022 x 10^23 atoms make up one mole (Avogadro's number). Thus, divide 6.85 x 10^25 atoms by Avogadro's number to get the number of moles. Therefore, the number of moles of potassium in this case would be 11.4 moles.
In potassium dichromate (K2Cr2O7), there are 7 oxygen atoms per molecule. Therefore, two moles of K2Cr2O7 would contain 14 moles of oxygen atoms. Each mole of oxygen atoms has a molar mass of approximately 16 grams, so there would be 224 grams of oxygen in two moles of potassium dichromate.
In 2 moles of potassium dichromate, there are 16 moles of oxygen atoms (from the two oxygen atoms in each formula unit). The molar mass of oxygen is 16 g/mol, so in 2 moles of potassium dichromate, there are 32 grams of oxygen.
3KNO3, so 9 oxygen atoms.
0.3 moles K (6.022 X 10^23/1mol K) = 1.8 X 10^23 atoms of K
10.0 moles K2SO4 (6.022 X 1023/1 mole K2SO4) = 6.02 X 1024 atoms of potassium sulfate ==========================