10.8 grams silver (1 mole Ag/107.9 grams)(6.022 X 1023/1 mole Ag)
= 6.03 X 1022 atoms of silver
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108g is 0.238 pound.
One formula unit of silver sulfate, Ag2SO4 has 7 atoms.
It depends on the weight of the silver in the material. 107.89 g of silver will have 6.023 x 1023 atoms of silver
5 :)
Silver chlorate has the formula AgClO3 which gives 5 atoms: 1 silver, 1 chlorine, and 3 oxygen.
The atomic mass of the element silver, Ag is 108Amount of Ag = mass of sample/molar mass = 108/108 = 1.00 So, there is 1.00mol of silver in a 108g pure sample.
1 mole of silver would be 108g and 1 mole of gold 197g.
The answer is approx. 1,5.10e23 atoms of silver.
Silver is an atom.
Silver is an atom.
29
108g is 0.238 pound.
Silver is an element, pure silver would contain only silver atoms.
about 30
There are 6.022x1023 atoms in a mole. You multiply 6.022x1023 by 8.68, which equals 52.20796x1023 atoms
One formula unit of silver sulfate, Ag2SO4 has 7 atoms.
It depends on the weight of the silver in the material. 107.89 g of silver will have 6.023 x 1023 atoms of silver