Oxygen has six valence electrons.
There are 4 valence electrons on the oxygen atom in the water molecule. Oxygen has 6 valence electrons, and in a water molecule, oxygen forms 2 covalent bonds with the hydrogen atoms, sharing 2 of its valence electrons with each hydrogen atom.
A neutral atom of oxygen would have 6 valence electrons.
An oxygen atom has two valence electrons.
Valence electrons are shared between oxygen atoms, Four valence electrons are shared.
Serine has five valence electrons. It has three valence electrons from the oxygen atom and one valence electron each from the carbon and nitrogen atoms in its structure.
CH3CO-OH (acetic acid) has 10 valence electrons. The carbon atom contributes 4 valence electrons, each hydrogen atom contributes 1 valence electron, and the oxygen atom contributes 6 valence electrons.
The answer is c. Valence electrons are shared between oxygen atoms & D. Four valence eletrons are shared
An unbonded oxygen atom has eight electrons, with six of the electrons located in the valence shell. Two of the valence electrons are unpaired, and therefore can undergo covalent bonding with other oxygen atoms or nonmetals (such as hydrogen).
The H3O+ ion has three hydrogen atoms bonded to an oxygen atom. Each hydrogen atom contributes 1 valence electron, while the oxygen atom contributes 6 valence electrons. Therefore, the total number of valence electrons in the H3O+ ion is 3 (hydrogen) + 6 (oxygen) = 9 electrons.
To draw the Lewis structure of 2CO2, you first need to determine the total number of valence electrons. Each oxygen atom contributes 6 valence electrons, and each carbon atom contributes 4 valence electrons, for a total of 16 + 4 = 20 valence electrons. Place the carbon atom in the center, surrounded by two oxygen atoms. Each oxygen atom forms a double bond with the carbon atom, using 4 electrons each. This leaves 4 electrons to be placed as lone pairs on each oxygen atom to satisfy the octet rule.
The answer is not 6 as said here before! The number of valence electrons in O2 (oxygen molecule) is: 12 valence electrons. 6 of them from each oxygen (O) atom. 4 valence electrons make up the double bond between the two oxygen atoms, and the remaining 8 valence electrons form lone pairs (non-bonding pairs) on the oxygen atoms, 2 lone pairs on each. I hope there is some help in this.
H2O2 is a compound, and the concept of "valence electrons" applies to atoms but not to compounds. If the question is or should be intended to be, "How many valence electrons did the atoms in one formula unit of H2O2 have before they reacted to form the compound?", the answer is one from each hydrogen atoms and six from each oxygen atom, for a total of 14.