Assuming you're talking about bits, the answer is always "2 to the x power" where in this case x is 3.
This is obviously a homework question, so instead of giving you the answer, I'll give you the explanation.
In the case of 4 bits, you'd have 16 values possible. 8 bits would be 256.
If you consider a bit to be a digit where the lowest number is 0 and the highest number is 1, then there are 2 possible values a bit can be. In the case of decimal (your normal counting numbers), the lowest value is 0 and the highest is 9 which is a maximum of 10.
If you have 3 decimal digits, there are 1000 possible decimal sequences or combinations that those numbers can be. Starting at 000 and working up to 999.
So you can calculate that by saying 10 to the 3rd power or 10x10x10 is 1000.
If you're solving for 2, then you'd multiply by 2 instead of 10. For example if you had 5 binary digits, your biggest number will be 11111 which is 31 in decimal, which means 5 digits of binary can go from 00000 to 11111 or 0 to 31. Or 32 possible values.
You can calculate this easily by multiplying 2 five times. 2x2x2x2x2 = 32.
For a full binary tree of height 3 there are 4 leaf nodes. E.g., 1 root, 2 children and 4 grandchildren.
1. Binary Tree 2. Null Tree 3. High&Low Balance Tree . . .
To convert from binary to octal, bitwise AND the binary value with 0x8 (00000111 in binary) and push the value onto a stack. Right-shift (>>) the binary value by 3 bits and repeat until the binary value is zero. Pop the stack to build the left-to-right digits of the octal value. Using 10110100 as an example: 10110100 & 00000111 = 00000100 10110100 >> 3 = 00010110 00010110 & 00000111 = 00000110 00010110 >> 3 = 00000010 00000010 & 00000111 = 00000010 00000010 >> 3 = 00000000 Popping the values in order reveals 00000010, 00000110 and 00000100 (decimal 2, 6 and 4 respectively). Thus 10110100 binary is 0264 octal.
3
If necessary, pad the value with zeroes so the number of bits is an exact multiple of 3. Then divide the binary value into groups of 3 bits. Convert each group to its corresponding octal digit as follows: Bin = Oct 000 = 0 001 = 1 010 = 2 011 = 3 100 = 4 101 = 5 110 = 6 111 = 7 Example 1: 16-bit value: 1011101101100011 3-bit groupings: (00)1 011 101 101 100 011 Octal digits: 1 3 5 4 3 Octal value: 13543 Example 2: 24-bit value: 010111011010010101011010 3-bit groupings: 010 111 011 010 010 101 011 010 Octal digits: 2 7 3 2 2 5 3 2 Octal value: 27322532
12 memory sequences
Three numbers can be arranged in 27 different sequences if repetition is allowed, and in 6 different sequences if it's not.
3 words
Binary form has 2 sections,Ternary form has 3 sections.
3 in binary is 11
81024+361+3 = 81388 81388 in binary is 10011110111101100
3 converted into binary code is 00000011
3 items (or people) can line up in 6 different sequences. 6 items (or people) can line up in 720 different sequences.
11 in binary form: 1011 11 is binary form of 3
3! = 6 different sequences =================
A Binary Number is made up of only 0s and 1s. 110100 Example of a Binary Number There is no 2, 3, 4, 5, 6, 7, 8 or 9 in Binary! A "bit" is a single binary digit. The number above has 6 bits. Binary numbers have many uses in mathematics and beyond.
1) Gypsy Love Song,2) Mendelssohn's Lieder Ohne Worte,3) Chopin's Waltzes and Nocturnes