8 bit input is given to Intel 8085 microprocessor.
Because it is an 8-bit microprocessor.
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An 8 bit microprocessor is a 'microprocessor' which only has an 8 bit wide databus.
It is depended on how many bits the processor can process simultaneous... Means 8 bit microprocessor can process 8 bit of data simultaneously... & also it has 8 line data bus.. to transfer the data between memory & IO devices.... In same way for 64 bit..
The disadvantage of the bit slice microprocessor is that it is slow that it why it was slow with earlier processors.
it is a 16 bit microprocessor & it has 40 pin .
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The main advantage of a 64 bit operating system is that it can make use of all the features and performance of a modern 64 bit microprocessor. If you run a 32 bit operating system on a modern 64 bit microprocessor the operating system will not be able to make use of any 64 bit features of the microprocessor and the performance will not be what the microprocessor is capable of.However a 64 bit operating system WILL NOT run at all on a 32 bit microprocessor (or one with a smaller word size) as the microprocessor does not implement the 64 bit features needed for the operating system to work.Note: in the not too distant future microprocessor manufacturers will release 128 bit microprocessors, which will require 128 bit operating systems to use all the features and performance of these microprocessors.
The 8085 is an 8-bit microprocessor. Even though there are some 16-bit registers (BC, DE, HL, SP, PC), with some 16-bit operations that can be performed on them, and a 16-bit address bus, the accumulator (A), the arithmetic logic unit (ALU), and the data bus are 8-bits in size, making the 8085 an 8-bit computer.
The Intel 8080 was the first microprocessor using an 8 bit databus.
8085 is a 8 bit microprocessor designed by Intel Co.
micro organisition means there are many types of chip in side the cpu they are 60 bit 70 bit