a.
Logical address will have
3 bits to specify the page number (for 8 pages) .
10 bits to specify the offset into each page (210 =1024 words) = 13 bits.
b.
For (25) 11 32 frames of 1024 words each (Page size = Frame size)
We have 5 + 10 = 15 bits.
4 pages -> 2^2 bits 1024 bytes -> 2^10 bits 64 frames -> 2^6 bits Therefore: Logical memory = 2+10=12 bits Physical memory = 10 +6 =16 bits
physical address
As was given for a 4 Page, 1024 words & 64 frames (shown below) 4 pages -> 2^2 bits 1024 bytes -> 2^10 bits 64 frames -> 2^6 bits Therefore: Logical memory = 2+10=12 bits Physical memory = 10 +6 =16 bits The answer for this problem is 13. 8 pages -> 2^3 bits 1024 bytes -> 2^10 bits 32 frames -> 2^5 bits Therefore: Logical memory = 3+10=13 bits (Page + Word) Physical memory = 10 + 5 =15 bits (Word + Frame)
destination (physical/hardware address) Source (physical/hardware address) Start flag (start of message indicator) Recipient sender encapsulated data end of frame
yes i think, because the MAC address is the physical address which is assigned by the vendor of the Ethernet card. ** Improved Answer ** No, Unmanaged switches do not have a MAC address. All they do is filter, forward or flood frames.
in the osi model data link layer is adds source & destination mac address to frames
The address of the beginning of a page frame is found by multiplying the page frame number by the number of frames.
The physical layer of the OSI model is responsible for encoding frames in to the electronic/RF/optical signals of the physical medium and for reading the media and translating back in to usable frames.
the source Layer 2 address of incoming frames
switch
It stores frames in temporary buffer space it floods and notes the source address it associates the source address with a particular port.
they maintain a filtering database that identifies which frames can be filtered and which should be forwarded, based on their destination MAC address.