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How many host bits are necessary to assign addresses to 62 hosts?
6
Maximum number of hosts class c Address?
254 - a class C subnet uses 8 bits for the hosts and 0 and 255 are reserved.
What is a group of hosts called that have identical bit patterns in the high order bits of their addresses?
A Network
What is a group of hosts called that have identical bit pattern in the high order bits of their addresses?
A Network
What is the maximum number of hosts that can be served by an IP?
The maximum number of hosts that can be served by an IP address depends on the subnet mask used. In IPv4, a typical subnet allows for 2^n - 2 hosts, where n is the number of bits available for host addresses (the total bits minus the bits used for the network). For example, a /24 subnet (255.255.255.0) provides 256 addresses, allowing for 254 usable hosts. In IPv6, the address space is vast, allowing for an effectively unlimited number of hosts due to its 128-bit structure, providing 2^128 possible addresses.
How many hosts are addressable on a network that has a mask of 255.255.255.248?
A subnet mask of 255.255.255.248 corresponds to a /29 prefix, which means there are 3 bits available for host addresses (since 32 bits total - 29 bits for the network = 3 bits for hosts). The formula for calculating the number of addressable hosts is 2^n - 2, where n is the number of host bits. Thus, 2^3 - 2 equals 6 addressable hosts on this network.
How many bits are in 172.168.2.0 26 subnet?
The subnet mask for a /26 subnet indicates that the first 26 bits are used for the network portion, leaving 6 bits for the host portion. In this case, the subnet 172.168.2.0/26 can accommodate 2^6 = 64 addresses, but only 62 are usable for hosts (subtracting the network and broadcast addresses). Thus, there are 26 bits designated for the network and 6 bits for hosts within this subnet.
How many hosts in 512 subnets?
To determine the number of hosts in 512 subnets, we first need to understand the subnetting. If you have 512 subnets, that means you need 9 bits (since 2^9 = 512). Assuming you are using a standard classful subnet mask, the remaining bits from a total of 32 bits (IPv4) can be used for hosts. This would typically leave you with 23 bits for hosts, allowing for 2^23 - 2 = 8,388,606 usable hosts per subnet, after accounting for network and broadcast addresses.
What is the range of usable IP addresses for 10.150.100.96 27?
That leaves us 5 bits for the host (32 - 27 = 5); the size of the network is 25 = 32 IP addresses, that is, addresses 10.150.100.96 - 10.150.100.127. The first and last address are not usable (can't be assigned to hosts), which leaves us with addresses 10.150.100.97 - 10.150.100.126.That leaves us 5 bits for the host (32 - 27 = 5); the size of the network is 25 = 32 IP addresses, that is, addresses 10.150.100.96 - 10.150.100.127. The first and last address are not usable (can't be assigned to hosts), which leaves us with addresses 10.150.100.97 - 10.150.100.126.That leaves us 5 bits for the host (32 - 27 = 5); the size of the network is 25 = 32 IP addresses, that is, addresses 10.150.100.96 - 10.150.100.127. The first and last address are not usable (can't be assigned to hosts), which leaves us with addresses 10.150.100.97 - 10.150.100.126.That leaves us 5 bits for the host (32 - 27 = 5); the size of the network is 25 = 32 IP addresses, that is, addresses 10.150.100.96 - 10.150.100.127. The first and last address are not usable (can't be assigned to hosts), which leaves us with addresses 10.150.100.97 - 10.150.100.126.
A network with 6 bits remaining for the host portion will have how many usable hosts and 8203?
A network with 6 bits remaining for the host portion can accommodate (2^6 = 64) total addresses. However, two addresses are reserved: one for the network address and one for the broadcast address. Therefore, the number of usable hosts in this network will be (64 - 2 = 62).
Which two statements describe classful IP addresses?
The number of bits used to identify the hosts is fixed by the class of the network. Up to 24 bits can make up the host portion of a Class C address.
What netmask would you use to allow for 310 hosts in a subnet?
To accommodate 310 hosts in a subnet, you would need a netmask that provides at least 512 IP addresses, as the number of usable host addresses is calculated as (2^{(32 - n)} - 2), where (n) is the number of bits used for the network portion. A /23 netmask (255.255.254.0) allows for 512 total IP addresses, resulting in 510 usable addresses after subtracting the network and broadcast addresses. Thus, a /23 netmask is suitable for a subnet requiring 310 hosts.
