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6
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How many host bits are necessary to assign addresses to 62 hosts?
6
Maximum number of hosts class c Address?
254 - a class C subnet uses 8 bits for the hosts and 0 and 255 are reserved.
What is a group of hosts called that have identical bit patterns in the high order bits of their addresses?
A Network
What is a group of hosts called that have identical bit pattern in the high order bits of their addresses?
A Network
How many hosts are addressable on a network that has a mask of 255.255.255.248?
A subnet mask of 255.255.255.248 corresponds to a /29 prefix, which means there are 3 bits available for host addresses (since 32 bits total - 29 bits for the network = 3 bits for hosts). The formula for calculating the number of addressable hosts is 2^n - 2, where n is the number of host bits. Thus, 2^3 - 2 equals 6 addressable hosts on this network.
How many bits are in 172.168.2.0 26 subnet?
The subnet mask for a /26 subnet indicates that the first 26 bits are used for the network portion, leaving 6 bits for the host portion. In this case, the subnet 172.168.2.0/26 can accommodate 2^6 = 64 addresses, but only 62 are usable for hosts (subtracting the network and broadcast addresses). Thus, there are 26 bits designated for the network and 6 bits for hosts within this subnet.
What is the range of usable IP addresses for 10.150.100.96 27?
That leaves us 5 bits for the host (32 - 27 = 5); the size of the network is 25 = 32 IP addresses, that is, addresses 10.150.100.96 - 10.150.100.127. The first and last address are not usable (can't be assigned to hosts), which leaves us with addresses 10.150.100.97 - 10.150.100.126.That leaves us 5 bits for the host (32 - 27 = 5); the size of the network is 25 = 32 IP addresses, that is, addresses 10.150.100.96 - 10.150.100.127. The first and last address are not usable (can't be assigned to hosts), which leaves us with addresses 10.150.100.97 - 10.150.100.126.That leaves us 5 bits for the host (32 - 27 = 5); the size of the network is 25 = 32 IP addresses, that is, addresses 10.150.100.96 - 10.150.100.127. The first and last address are not usable (can't be assigned to hosts), which leaves us with addresses 10.150.100.97 - 10.150.100.126.That leaves us 5 bits for the host (32 - 27 = 5); the size of the network is 25 = 32 IP addresses, that is, addresses 10.150.100.96 - 10.150.100.127. The first and last address are not usable (can't be assigned to hosts), which leaves us with addresses 10.150.100.97 - 10.150.100.126.
A network with 6 bits remaining for the host portion will have how many usable hosts and 8203?
A network with 6 bits remaining for the host portion can accommodate (2^6 = 64) total addresses. However, two addresses are reserved: one for the network address and one for the broadcast address. Therefore, the number of usable hosts in this network will be (64 - 2 = 62).
Which two statements describe classful IP addresses?
The number of bits used to identify the hosts is fixed by the class of the network. Up to 24 bits can make up the host portion of a Class C address.
What netmask would you use to allow for 310 hosts in a subnet?
To accommodate 310 hosts in a subnet, you would need a netmask that provides at least 512 IP addresses, as the number of usable host addresses is calculated as (2^{(32 - n)} - 2), where (n) is the number of bits used for the network portion. A /23 netmask (255.255.254.0) allows for 512 total IP addresses, resulting in 510 usable addresses after subtracting the network and broadcast addresses. Thus, a /23 netmask is suitable for a subnet requiring 310 hosts.
How many individual systems can be subnet with netmask 255.255.240.0?
A netmask of 255.255.240.0 corresponds to a /20 subnet, which provides 12 bits for host addresses (32 total bits minus 20 bits for the network). This allows for (2^{12} - 2 = 4096 - 2 = 4094) usable individual systems, accounting for the network and broadcast addresses that cannot be assigned to hosts.
Which class of ip addresses offers the most flexibility for subnetting by providing for the largest number of hosts?
A class A would give you the most flexibility in terms of subnets and hosts per subnet. You could use up to 23 bits of information for subnets.
