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To determine the number of hosts in 512 subnets, we first need to understand the subnetting. If you have 512 subnets, that means you need 9 bits (since 2^9 = 512). Assuming you are using a standard classful subnet mask, the remaining bits from a total of 32 bits (IPv4) can be used for hosts. This would typically leave you with 23 bits for hosts, allowing for 2^23 - 2 = 8,388,606 usable hosts per subnet, after accounting for network and broadcast addresses.
What else can I help you with?
How many subnets and hosts per subnet can you get from the network 172.16.0.0?
There are 16 bits available; it is up to you how many of those bits you reserve for the subnet, and how many for the individual hosts within each subnet.
How many subnets of 300 hosts can be created on a network of IP address 172.16.1.0?
1
In a class A how many subnet bits are needed to make at least 365 useable hosts or subnets?
You would need at least 9 bits to borrow. Since 8 bits gives only 255 the additional bit will get you 256. Adding 256 + 128 gives you at least 384 subnets or hosts.
Which subnet mask should be used for a class B network that is divided into subnets that will accommodate between 800 hosts and 1000 hosts?
255.255.252.0
Which subnet mask should be used for a Class B network that is divided into subnets and will accommodate between 800 hosts and 1000 hosts?
255.255.252.0
Which class of ip addresses offers the most flexibility for subnetting by providing for the largest number of hosts?
A class A would give you the most flexibility in terms of subnets and hosts per subnet. You could use up to 23 bits of information for subnets.
How many subnets are required to support the network shown?
To determine the number of subnets required, you need to know the number of distinct network segments or groups of devices that require separate IP address ranges. Each subnet typically supports a specific number of hosts, and the total demand for hosts across all segments will dictate how many subnets are necessary. If you provide more specific details about the network layout or the number of devices, I could give a more precise answer.
How many subnets and hosts per subnts can you get from 172.30.0.0?
The IP address 172.30.0.0 is a private IP address in the Class B range, which has a default subnet mask of 255.255.0.0 (or /16). If you use the default mask, you can create 65,536 addresses (2^16), allowing for 65,534 usable hosts per subnet (subtracting 2 for the network and broadcast addresses). If you further subnet this address, the number of subnets and hosts per subnet will depend on the subnet mask you choose. For example, using a /24 subnet mask would give you 256 subnets with 254 usable hosts in each.
Given class C address with a default subnet mask How many possible subnets and usable hosts if 4 bits were borrowed?
that gives you 16 subnets with 14 usable IPs for hosts that is because one is for subnet and one for broadcas in that subnet for example: 192.168.1.0/28 - subnet number 192.168.1.15 -broadcast number usable IPs for hosts - IPs between them that is 14
What mask would you assign to the network ID of 172.16.0.0 if you needed about 100 subnets with 500 hosts each?
255.255.252.0
What are necessary procedure in calculating subnet mask or simply subneting show an example forr calculation?
To calculate a subnet mask, first determine the number of subnets needed and the number of hosts per subnet. Use the formula (2^n \geq \text{number of subnets}) for subnetting and (2^h - 2 \geq \text{number of hosts}) for host calculation, where (n) is the number of bits borrowed for subnets and (h) is the number of bits left for hosts. For example, if you start with a Class C address like 192.168.1.0 and want 4 subnets, you would borrow 2 bits (since (2^2 = 4)), resulting in a subnet mask of 255.255.255.192 (or /26), which allows for 62 hosts per subnet.
How many host can you have with 255.255.254.0?
The subnet mask 255.255.254.0 corresponds to a /23 prefix, which allows for 512 IP addresses in total (2^(32-23)). However, two addresses are reserved: one for the network and one for the broadcast. Therefore, the number of usable hosts is 512 - 2 = 510 hosts.
