log(number of generations) / log(2)
Round the answer up.
40 bits or 5 byrtes
4
about eight bits, which is equal to one byte
To determine how many bits are required to store a specific value, you need to know the range of values that must be represented. The formula to calculate the number of bits (n) needed is ( n = \lceil \log_2(V) \rceil ), where ( V ) is the number of unique values. For example, to store integers from 0 to 255 (256 values), you would need 8 bits, since ( \log_2(256) = 8 ).
3 bits
21 bits.
5 bits
In ASCII code, each letter, number or punctuation mark takes one byte, or 8 bits. That gives you 256 discrete combinations. Two letters take 2 bytes, or 16 bits.
28-bits
4
4
for two n bits multiplication results produce 2n bits