Three bonding pairs, thus a pyramid.
One lone pair and three bonding chlorine pairs. General shape is tetrahedral and it's a trigonal pyramidal.
3 bond pairs and no lone pairs
Each iodine atom in a molecule of carbon tetraiodide has three non-bonding pairs of electrons.
you have 5 binded elektron pairs, and one free pair
Four pairs.
One lone pair and three bonding chlorine pairs. General shape is tetrahedral and it's a trigonal pyramidal.
NONE!!! Each bonding electron in carbon is paired with the bonding electron in each of the four hydrogens. So there are no lone pairs.
There are four electrons, which is two pair.
3 bonding pairs and one lone pair or non-bonding pair
There are three bonding pairs of electrons in BF3. There are 0 nonbinding pairs, but BF3 can accept two more electrons to give it a complete octet
3 bond pairs and no lone pairs
bp-4,lp-1
Cl4 doesn't exist. It should be Cl2 and there will be 4 pairs of non bonding electrons on each chlorine.
Due to the VSEPR theory (the valence shell electron pair repulsion theory) It has a tetrahedral shape because it has four negative charge centres. When there are four negative charge centres and all there are four bonding pairs of electrons the shape is tetrahedral. for future reference any atom with 4 negative charge centres will have the following structures (depending on how many of the electron pairs (negative charge centres) are bonded): all bonding pairs: tetrahedral (for example ccl4, ch4 nh4 bf4) 3 bonding and 1 non bonding: trigonal pyramid (e.g. ammonia) 2 bonding and 2 non bonding: bent (v-shaped) - for example water.
An HCl molecule contains 3 nonbonding pairs..
9
Serine does not have any non-bonding electrons pairs. Please click on the related link to see a structural formula for serine.