Cl4 doesn't exist. It should be Cl2 and there will be 4 pairs of non bonding electrons on each chlorine.
There is no such substance as (CH)(Cl4).
Divide the Molar Mass of C and Cl4 by 56 to get your awnswer!
Carbon tetrachloride would be... CCl4 There are 4 electrons in C and 28 in Cl4... 28 + 4 = 32 So you have 32 electrons that you need to somehow disperse. C is your central atom...so your 4 Cl will be surrounding it Cl | Cl-C-Cl | Cl (....I wish we could draw stuff out on here. Sigh*) So there you have 4 bonds already...which ='s 8 electrons...so you have 24 more you need to disperse. In order to make each Cl "happy" it needs 8 electrons. Since they already have 2 electrons with the bond to C, each one just need 6. You have 4 Cl that need 6 electrons. 6+2=8..YAYYYY...so just put 6 more electrons around each Cl...so that means that there are no more bonds...there are only 4 single bonds.
Ethanol is a polar molecule because of the hydroxyl group (CH3CH2-OH). Carbon tetrachloride (C-CL4) is non-polar and does not exhibit hydrogen bonding. Many organic compounds are water soluble because of their polar nature i.e. acetone, citric acid, and others.
The bonds in CCl4 are polar covalent.
There is no such substance as (CH)(Cl4).
CL4
Divide the Molar Mass of C and Cl4 by 56 to get your awnswer!
1 carbon and 4 chlorine
cl4
Carbon tetrachloride would be... CCl4 There are 4 electrons in C and 28 in Cl4... 28 + 4 = 32 So you have 32 electrons that you need to somehow disperse. C is your central atom...so your 4 Cl will be surrounding it Cl | Cl-C-Cl | Cl (....I wish we could draw stuff out on here. Sigh*) So there you have 4 bonds already...which ='s 8 electrons...so you have 24 more you need to disperse. In order to make each Cl "happy" it needs 8 electrons. Since they already have 2 electrons with the bond to C, each one just need 6. You have 4 Cl that need 6 electrons. 6+2=8..YAYYYY...so just put 6 more electrons around each Cl...so that means that there are no more bonds...there are only 4 single bonds.
Ethanol is a polar molecule because of the hydroxyl group (CH3CH2-OH). Carbon tetrachloride (C-CL4) is non-polar and does not exhibit hydrogen bonding. Many organic compounds are water soluble because of their polar nature i.e. acetone, citric acid, and others.
The bonds in CCl4 are polar covalent.
Yes, tetraiodomethane is covalently bonded.
CaCl2 + 2HCl ---> CaH2 + Cl4
Cl4 does not exist, but if CCl4 is meant: this is a nonpolar compound
boron tetra chloride