Cyanogen bromide is a molecule consisting of three atoms. There is a central carbon atom triple-bonded to a nitrogen on one side and single-bonded to a bromine on the other side. The C-N triple bond consists of one sigma bond and two pi bonds, while the C-Br single bond is one sigma bond. The angle between the two bonds is 180 degrees, making this a linear molecule. The central carbon is sp-hybridized.
Si will have two bonds to the two Hydrogens, and a double bond to the Oxygen. The Oxygen will have two pairs of unpaired valence electrons.
Ammonia can form four hydrogen bonds per molecule. The lone pair on nitrogen can accept one hydrogen to form a hydrogen bond, and the three hydrogen atoms can bond to lone pairs to form three additional hydrogen bonds. However, if ammonia is the only molecule present, this bonding pattern is problematic because each molecule only has one lone pair per three hydrogen atoms. Thus, an average molecule would likely only have two hydrogen bonds, out of the maximum of four.
Any molecular formula will tell you how many atoms are in it. I don't want to just give you the answer so let's use another atom...C6H12O6. Your basic monosaccharide. It has... 6 carbon atoms 12 hydrogen 6 oxygen Add 'em up and you get 24 atoms. An atom that doesn't have a number behind it has only one example of it in each molecule...CH4 has one carbon and four hydrogens.
Ammonium bromide - NH4Br - contain 6 atoms.
1
Two. covalent bonds in the ammonium ion NH4+ and ionic bond between the ammonium ion and the bromide ion, Br-
There are five covalent bonds present in an ethyne molecule.
There are two double bonds in a carbon dioxide molecule.
There are two double bonds in a carbon dioxide molecule.
There are two double bonds in a carbon dioxide molecule.
SF has a single bond but it is not a molecule.
The formula unit of beryllium bromide contain one molecule.
Two.
13 sigma bonds and 0 pi bonds
2
9
sigma bonds=9 and pi bonds=2