Three is the answer expected. Higher valences of phosphorus, in PCl5 for example can be explained by hybridisation although this method is not the only explanation.
0 bonds
The C atom of HCHO has 3 sigma bonds and a pi bonds. Hence the hybridization of C is sp2.
The valence electrons of O is 6 and F is 7. 7x2= 14 + 6 =20 electrons in totalEach Fluorine makes a single bond with the oxygen atom. so that's 2 bonds right there.then fill up the fluorines so that they are satisfied. 16 electrons have now been used up. But the oxygen atom is still unsatisfied so you must give the oxygen atom 2 lone pairs. the total is now 20 electronsnow the hybridization of the oxygen atom which in this case is the central atom is determined by adding the total # of bonds together, it has 2 bonds with Fluorine and two lone pairs, add them up and u get 4 total bonds. 4 total bonds is = to sp^3
There are 4 carbon atoms, which each individually act as a central atom since they are surrounded entirely by the hydrogen atoms. Each carbon forms 4 sigma bonds, therefore, each carbon atom has a hybridization state of sp^3.
Sp3 d
0 bonds
It depends on the hybridization of the central atom.
The C atom of HCHO has 3 sigma bonds and a pi bonds. Hence the hybridization of C is sp2.
The valence electrons of O is 6 and F is 7. 7x2= 14 + 6 =20 electrons in totalEach Fluorine makes a single bond with the oxygen atom. so that's 2 bonds right there.then fill up the fluorines so that they are satisfied. 16 electrons have now been used up. But the oxygen atom is still unsatisfied so you must give the oxygen atom 2 lone pairs. the total is now 20 electronsnow the hybridization of the oxygen atom which in this case is the central atom is determined by adding the total # of bonds together, it has 2 bonds with Fluorine and two lone pairs, add them up and u get 4 total bonds. 4 total bonds is = to sp^3
There are 4 carbon atoms, which each individually act as a central atom since they are surrounded entirely by the hydrogen atoms. Each carbon forms 4 sigma bonds, therefore, each carbon atom has a hybridization state of sp^3.
Sp3 d
That would be Trigonal Pyramidal in shape and have an sp3 hybridization.
If the given compound exists, there'll be 4 sigma bonds and a single remaining electron in the valence shell of the central atom. With 5 activation groups, the hybridization would be sp3d.
Sp2,120 is the hybridization of the central atom in SO2.
wo. A strange question! if you hybridise the 3s and 3 p orbitals you end up with sp3 and still get the same answer. Perhaps the hybridisation involves d orbitals, if that is what you are being taught.
There is no central atom in P4O6. The molecule has a tetrahedron of P atoms where the P atoms are helf together by briding oxygen atoms.
The central atom P is bonded to the five chlorine atoms by five single covalent bonds. So, the total number of single bonds is 5. The hybridization must be among one s orbital, three p orbitals and one d orbital each of which has a half filled orbital to share with the half filled orbital of each chlorine atom. So the hybridization can be written as sp3d. 1s, 3p and 1 d, a total of 5. An easy way to find the hybridization is to count the number of bonds including the unshared electrons around the central atom. For double or triple bond count only one. If the total number of bonds including the number of unshared electron pairs is 6, then the hybridization will be sp3d2, a total of 6.