That's going to depend on how much water you're responsible for.
Teacup at 60 degrees . . . very few BTU.
Swimming pool at 60 degrees . . . many more BTU.
It's also going to depend on whether you're talking about Celsius or Fahrenheit degrees.
Fahrenheit degrees . . . fewer BTU.
Celsius degrees . . . more BTU. (Also, the water will escape as you pass 100.)
In general, one BTU is approximately the energy required to raise the temperature
of 1 pound of water 1 degree Fahrenheit. You can take it from there, when you reach
the job site and determine the exact scope of the work.
That will completely depend on how much water there is.
U.S.gallon = 8.33 pounds of water. Therefore to raise the temperature by one degree F will require 8.33 BTU. The initial temperature of 50 F is inconsequential.
To raise the temperature of one cc of water requires i calorie of heat . you did not specify the volume.
2250
q (amt of heat) = mass * specific heat * temp. differenceThe specific heat of water is 1.00 cal/goC & the temperature difference is 70-30 = 40oCq = (105 grams)*(1.00 cal/goC)*(40oC)= 4,200 calories
That will completely depend on how much water there is.
12 degrees Celsius
12 degrees Celsius
15480.80
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
U.S.gallon = 8.33 pounds of water. Therefore to raise the temperature by one degree F will require 8.33 BTU. The initial temperature of 50 F is inconsequential.
1 calorie is the energy required to raise 1 gram of water by 1 degree C. So it would take 5 calories to raise it by 5 degrees C.
21 grams through 71 degrees is 21x71 calories.
To raise the temperature of one cc of water requires i calorie of heat . you did not specify the volume.
Kilowatts is a unit of energy rate, while the temperature required to raise a specific volume of water by a specific amount of degrees is a unit of energy, not energy rate. The question cannot, therefore, be answered as stated. Please restate the question.
15.37684 joules
It depends on what temperature is is at and how much water there is.