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Using Ohm's Law E=IR, we would need four 8 ohm bulbs in parallel to draw a total circuit current (I sub t) of 2 amps. Each of the four branches would have .5 amps flowing through the bulb.

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Q: How many bulbs of 8 ohms should be joined in parallel to draw a current of 2 Amphere from a battery of 4 volt?
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