How many calories are required to raise the temperature of 225 gram of water from 42 to 75 degrees Celsius?

Answer 1

6100 calories It takes 10 calories to raise the 10 grams of water each degree celsius. So, a temperature change of 70 degrees celsius requires 700 cal. 540 cal/g x 10g=5400 cal 5400 cal + 700 cal= 6100 calories

Answer 2

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Answer 3

The specific heat of water is 1 calorie/g-ºC.

So in order to find the number of calories required to raise 225g of water from 42 to 75 degrees, the equation is q=mCp delta T

Meaning, heat equals mass x specific heat x change in temperature

q = 225 g x 1 calorie/g-ºC x (75ºC-42ºC)

q= 225 calorie/ºC x 33ºC

q=7425 calories

Answer 4

calories=mass x specific heat capacity x change in temp

so Calories = 225 x 1/1 x 33

calories =7425

Answer 5

1 calorie will raise 1 g of water by 1 degree C. So, multiply 105 g by the change in temperature to get the the total calories needed.

Answer 6

The necessary heat is 1 calorie for 1 g and 1 oC.

Answer 7

4.20x103