105C
The amount of water whose temperature would change by 15 degrees Celsius when it absorbs 2646 joules of heat energy is 42,2g H2O.
The number of calories required will depend on the mass of water which is to be heated.
Liquid water absorbs 1 calorie per (gram °C)Temperature difference = 100°C - 23°C = 77°C(50 g) * (77°C) * (1 cal/g/°C) = 3850 calories
115.2
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
Zero degrees Celsius.
25 degrees Celsius.
35 degrees Celsius.
9.14g
one calorie of heat is able to raise one gram of water one degree Celsius so 400 calories could raise 1g of water 400 degrees, so it would raise the 80g by(400/80) 5 degrees Celsius plus the initial temp of 10 degrees, the 80g of water would have a final temp of 15 degrees Celsius
The Celsius temperature of 32 degrees Fahrenheit would be 0 degrees.
32 degrees Fahrenheit = 0 degrees Celsius